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( 29=11,264 transistors. The 20 inverters require an additional 40 transistors.N =11304 transistors | (b) The number is the same.8.32 (a) NMOS Pass Transistor Tree: 2 x 20+21+22+23+24+25+26(29=254 Transistors2 logic inverters per level=14 inverters = 28 transistors.Total = 282 Transistors(b) An estimate: 128 data bits requires 128 7- input gates for data selectors;1 - 128 input NOR gate; 14 address bit invertersTotal =128 8( 29+1129(29+14 2( 29=1181 transistors without looking closely at the logic detail. A number of additional inverters may be needed,and the 128 input gate can likely be replaced with a smaller NOR tree.8.33See next page 8.34a( 29The output of the first NMOS transistor will beV1=5-VTN=5-0.75+0.55V1+0.6-0.6(29→V1=3.56V| VTN=1.44VThe output of the other gates reaches this same value. All three nodes = 3.56V.b( 29The node voltages will all be +5 V.
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