29 11264 transistors the 20 inverters require an

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( 29 = 11,264 transistors. The 20 inverters require an additional 40 transistors. N =11304 transistors | (b) The number is the same. 8.32 (a) NMOS Pass Transistor Tree : 2 x 2 0 + 2 1 + 2 2 + 2 3 + 2 4 + 2 5 + 2 6 ( 29 = 254 Transistors 2 logic inverters per level =14 inverters = 28 transistors. Total = 282 Transistors (b) An estimate : 128 data bits requires 128 7 - input gates for data selectors; 1 - 128 input NOR gate; 14 address bit inverters Total =128 8 ( 29 +1129 ( 29 +14 2 ( 29 =1181 transistors without looking closely at the logic detail. A number of additional inverters may be needed, and the 128 input gate can likely be replaced with a smaller NOR tree. 8.33 See next page 8.34 a ( 29 The output of the first NMOS transistor will be V 1 = 5 - V TN = 5 - 0.75 + 0.55 V 1 + 0.6 - 0.6 ( 29 [ ] V 1 = 3.56 V | V TN = 1.44 V The output of the other gates reaches this same value. All three nodes = 3.56V. b ( 29 The node voltages will all be +5 V.
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8-267 8.33 Clock Clock V DD V DD V DD V DD V DD V DD V DD V DD 0 1 2 3 4 5 6 7 NMOS Transistor A 0 A 1 A 2 8.34 See previous page
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