c The following drawing shows the relevant geometry r s celestial body person

# C the following drawing shows the relevant geometry r

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c. The following drawing shows the relevant geometry: r s celestial body person on earth pe rson on e arth moon r moon r sun s sun R sun sun moon s b R b  Chapter 8 Problems 389 2 2 2 0 (15 rad/s) –22 rad/s 2 2(5.1 rad)     b. With 0.0 rad /s for the skater’s final angular velocity, Equation 8.4 becomes 0 0 t . Solving for t , we obtain 0 2 15 rad/s 0.68 s –22 rad/s t     ____________________________________________________________________________________________ 21. SSM REASONING The angular displacement is given as θ = 0.500 rev, while the initial angular velocity is given as 0 = 3.00 rev/s and the final angular velocity as = 5.00 rev/s. Since we seek the time t , we can use Equation 8.6 1 2 0 t from the equations of rotational kinematics to obtain it.  #### You've reached the end of your free preview.

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• Fall '16
• Angular velocity, Velocity
• • • 