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4. 1/1 points | Previous Answers SCalcET7 4.1.039. Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) F ( x ) = x 4/5 ( x 8 ) 2 Solution or Explanation Click to View Solution 5. 1/1 points | Previous Answers SCalcET7 4.1.044. Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) f ( x ) = x 8 ln x = $$ e (18) x
12/14/16, 3)45 PM hw20S4.1 Page 4 of 10 6. 2/2 points | Previous Answers SCalcET7 4.1.055. Find the absolute maximum and absolute minimum values of f on the given interval. Solution or Explanation is not in the given interval, is not in the given interval. So is the absolute maximum value and is the absolute minimum value. f ( t ) = t , [ 1, 6 ] 36 t 2 absolute minimum value $$ −√ 35 absolute maximum value $$18 f ( t ) = t , [ 1, 6 ]. 36 t 2 f ' ( t ) = t · ( 36 t 2 ) 1/2 ( 2 t ) + ( 36 t 2 ) 1/2 · 1 = + = = . 1 2 t 2 36 t 2 36 t 2 t 2 + ( 36 t 2 ) 36 t 2 36 2 t 2 36 t 2 f ' ( t ) = 0 36 2 t 2 = 0 t 2 = 18 t = ± , but t = 18 18 [ 1, 6 ]. f ' ( t ) does not exist if 36 t 2 = 0 t = ± 6 , but 6 f ( 1) = , f ( ) = 18 , and f ( 6 ) = 0. 35 18 f ( ) = 18 18 f ( 1) = 35
12/14/16, 3)45 PM hw20S4.1 Page 5 of 10 7. 2/2 points | Previous Answers SCalcET7 4.1.057.MI.

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