The measured HCl was transferred to a 250mL Erlenmeyer flask 5 Three drops of

# The measured hcl was transferred to a 250ml

This preview shows page 3 - 5 out of 6 pages. CALCULATIONS: NaOH + HCl → NaCl + H2O Note: the concentration of the NaOH solution used was 0.216 M Trial 1: 0.216 M = → 0.00374 mol NaOH mol NaOH 0.0173 L NaOH ( )( ) = 0.00374 mol HCl 1 0.00374 mol NaOH 1 mol HCl 1 mol NaOH = .234 M 0.016 L HCl 0.00374 mol HCl Trial 2: 0.216 M = → 0.00238 mol NaOH mol NaOH 0.0110 L NaOH ( )( ) = 0.00238 mol HCl 1 0.00238 mol NaOH 1 mol HCl 1 mol NaOH = .238 M 0.010 L HCl 0.00238 mol HCl 0.216 M = → 0.0047088 mol NaOH mol NaOH 0.0218 L NaOH ( )( ) = 0.0047088 mol HCl 1 0.0047088 mol NaOH 1 mol HCl 1 mol NaOH = .235 M 0.020 L HCl 0.0047088 mol HCl ANALYSIS AND DISCUSSION: 1.When you titrate an acid with a base, you are advised to titrate to the faintest pink color. Why is this done?  #### You've reached the end of your free preview.

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• Winter '20
• pH, mol HCl
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