Total slack for g sl ls es 30 30 0 free slack for g

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Total Slack for G: SL= LS - ES = 30 - 30 = 0. Free Slack for G: FS = LF - EF = 40-40 = 0. Total Slack for H: SL= LS - ES = 40 - 40 = 0. Free Slack for H: FS = LF - EF = 45-45 = 0. 1 ID Activity Predecessor Time A Order review None 2 B Order standard parts A 15 C Produce standard parts A 10 D Design custom parts A 13 E Software development A 18 F Manufacture custom hardware C,D 15 G Assemble B,F 10 H Test E,G 5
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HW 4 IE5541 Sunny Ahmed The network diagram including early, late and slack times of the project for Air Control Company is as follows: Critical Path: There are four paths. A-B-G-H, A-C-F-G-H, A-D-F-G-H and A-E-H. A-B-G-H duration = 2+15+10+5 = 32 days. A-C-F-G-H duration = 2+10+15+10+5 = 42 days. A-D-F-G-H duration = 2+13+15+10+5 = 45 days. A-E-H duration = 2+18+5 = 25 days. Therefore critical path is A-D-F-G-H. 6-14. 2 2 E 2 0 2 0 2 0 2 2 1 8 4 0 4 0 H 4 5 0 0 4 0 5 4 5 E S ID EF SL FS LS DU R LF 5 E 7 8 Dev. Presen t 8 1 3 2 1 5
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HW 4 IE5541 Sunny Ahmed Network Forward Pass Calculations: For A: ES = 0. EF = ES + DUR = 0 + 3 = 3. ES = 0, EF = 3. DUR = 3. For B: ES = 3. EF = ES + DUR = 3 + 2 = 5. ES = 3, EF = 5. DUR = 2. For C: ES = 3. EF = ES + DUR = 3 + 3 = 6. ES = 3, EF = 6. DUR = 3. For D: ES = 6. EF = ES + DUR = 6 +7 = 13. ES = 6, EF = 13. DUR = 7. (EF of C greater than B). For E: ES = 5. EF = ES + DUR = 5 + 2 = 7. ES = 5, EF = 7. DUR = 2. For F: ES = 13. EF = ES + DUR = 13 + 2 = 15. ES = 13, EF = 15. DUR = 2. For G: ES = 6. EF = ES + DUR = 6 + 2 = 8. ES = 6, EF = 8. DUR = 2. For H: ES = 15. EF = ES + DUR = 15 + 1 = 16. ES = 15, EF = 16. DUR = 1. (EF of F greater than E and G). Network Backward Pass Calculations: For H: LF = 16. LS = LF - DUR = 16-1 = 15. LF = 16, LS = 15. DUR = 1. (EF = LF for last phase). For G: LF = 15. LS = LF - DUR = 15-2 = 13. LF = 15, LS = 13. DUR = 2. For F: LF = 15. LS = LF - DUR = 15-2 = 13. LF = 15, LS = 13. DUR = 2. For E: LF = 15. LS = LF - DUR = 15-2 = 13. LF = 15, LS = 13. DUR = 2. For D: LF = 13. LS = LF - DUR = 13 - 7 = 6. LF = 13, LS = 6. DUR = 7. For C: LF = 6. LS = LF - DUR = 6-3 = 3. LF = 6, LS = 3. DUR = 3. (LS of D is smaller than G).
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