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Post lab 7 & 8

The formula states that there are three oxygens which

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most likely a benzene ring. The formula states that there are three oxygen’s, which is proven by the IR spectra. The NMR spectra shows that there are two triplets, two doublets, and two singlets. The triplets are more towards the middle of the field, since they correlate with the C-C bonds around the ring. Since both of these are connected to two carbons, they each have three hydrogen’s and two neighboring hydrogen’s. The two doublets are each connected to one triplet and a C-O bond. This is why they only have two hydrogen’s and one neighboring hydrogen each. There is one singlet upfield and one that is downfield. The upfield one is connected to the single bonded oxygen and the downfield one is connected to the double bonded oxygen and the single bonded OH bond. Overall, the IR spectra, NMR proton spectra, and carbon NMR were all used together to form a structure for the molecular formula of C8H8O3. Conclusion: In this lab a H+ NMR, C-13 NMR, and an IR spectrum of an unknown compound were all conducted and analyzed in order to find out the compounds molecular formula and structure. The H NMR analysis predicted the number of hydrogen’s on each carbon and how many were neighboring. This allowed for them to be separated and placed into different fragments that made up the entire compound. The carbon NMR was used to predict the different carbon types for the eight different carbons involved in the structure. Lastly, the IR spectrum was used to predict what kind of stretches or bonds that were formed throughout the compound. The final formula came out to be C8H8O3, and the spectra’s help to prove it correct.
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