3 O and OH H 2 O H 2 O H 3 O OH Kw is the equilibrium constant K wH3 O x OH 100

3 o and oh h 2 o h 2 o h 3 o oh kw is the equilibrium

This preview shows page 3 - 4 out of 4 pages.

3 O + and OH - . H 2 O + H 2 O ↔ H 3 O + + OH - K w is the equilibrium constant, K w =[H 3 O + ] x [OH - ]=1.00 x 10 -14 In pure water or a neutral solution: [H 3 O + ]=[OH - ]= 1.0 x 10 -7 M In acidic solutions [H 3 O + ] >[ OH - ] and [H 3 O + ] > 1.0 x 10 -7 M and [OH - ] < 1.0 x 10 -7 M In basic solutions [H 3 O + ] < [ OH - ] and [H 3 O + ] <1.0 x 10 -7 M and [OH - ] >1.0 x 10 -7 M 11.6 The pH Scale pH= -log[H 3 O + ] pH < 7 pH = 7 pH > 7 11.7 Reactions of Acids and Bases 1. Acids react with many metals to produce H 2 and the salt of the metal, which causes corrosions of active metals. Zn (s) + HCl (aq) à ZnCl 2(aq) + H 2(g) 2. Acids react with salts of carbonates and bicarbonates to produce CO 2 + H 2 O+ another salt. CaCO 3 + 2HCl à CaCl 2 + CO 2 + H 2 O NaHCO 3 + HCl à NaCl + CO 2 + H 2 O 3. Acids and bases neutralize each other forming salts and water HCl + NaOH à NaCl + H 2 O 2HCl + Mg(OH) 2 à MgCl 2 +2H 2 O 3H 2 SO 4 + 2Al(OH) 3 à Al 2 (SO 4 ) 3 + 6H 2 O The net ionic equation of strong acid/base neutralization is H + + OH - à H 2 O Salts are ionic compounds that have cations of the base and anions of the acid.
Image of page 3
Acid-Base properties of salt solutions Salt components Example Explanation Salts of strong acids and strong bases produce neutral solutions, pH = 7. NaCl Neither Na + nor Cl - reacts with water. Salts of weak acids and strong bases form basic solutions, pH > 7. Na HCO 3 KF Li 3 PO 4 Na + doesn’t react with water; HCO 3 - reacts with water to produce its conjugate acid H 2 CO 3 and OH - . Thus, the solution is basic.
Image of page 4

You've reached the end of your free preview.

Want to read all 4 pages?

  • Fall '10
  • LingChen
  • pH, Acids, NH3

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern

Stuck? We have tutors online 24/7 who can help you get unstuck.
A+ icon
Ask Expert Tutors You can ask You can ask You can ask (will expire )
Answers in as fast as 15 minutes