We move the full reflect plate from 40 to 20cm and we transfer the equation X1

We move the full reflect plate from 40 to 20cm and we

This preview shows page 1 - 3 out of 3 pages.

We move the full reflect plate from 40 to 20cm, and we transfer the equation (X1-X2)= N λ/2 to λ=(X1-X2)2/N, and we can put X1=40cm, X2=20cm, and the N is 14 then we can get λ= 2.85714286. the real microwave wavelength, we use λ=c/f, which c is the velocity of the light( 3*10^8m/s), also we have the information of the transmitter of f is 10.5GHz which shows in the P3, from the equation we can get the λ is 0.02857142857143.
Image of page 1
P2(the data graph of the wave that move from 40cm to 20cm, and there are 14 peaks in the wave). X1(cm) X2(cm) N λ (cm) 40 20 14 2.86 P3( the information of the transmitter) Answers to questions 1. When it maximum that means two beams of light waves peaks are meat each other, the minimum of the wave means two beams of light waves are opposite. 2. No, because when I lean on the table, every part of the experiment is change in the same ration, so the whole equipment is still not change, if we change any single
Image of page 2
element inside the equipment, it will change the Maxima. 3. Because the visible light has higher frequency, it’s more accurate than the microwave. Conclusion The experiment is helping us to know how to calculate the wavelength through different methods, and we proved the equation of λ is true, and also we know the actual number of microwave wavelength.
Image of page 3

You've reached the end of your free preview.

Want to read all 3 pages?

  • Fall '12
  • BorisSinkovic
  • Light, Michelson interferometer, 8m/s, 2.86cm, 2.857142857cm

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern

Stuck? We have tutors online 24/7 who can help you get unstuck.
A+ icon
Ask Expert Tutors You can ask You can ask You can ask (will expire )
Answers in as fast as 15 minutes
A+ icon
Ask Expert Tutors