# Consider the circuit below where the ca pacitor is

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006 10.0points R C E S Since the current in an R C circuit is I = E R e - t/ ( RC ) and the voltage across the resistor is V = I R , V f R = E R e - t/ ( RC ) t = - R C ln parenleftbigg V f E parenrightbigg = - (20 Ω)(4 × 10 - 7 F) ln parenleftbigg 13 V 19 V parenrightbigg Consider the circuit, below, where the ca-
pacitor is initially uncharged and the switch is open. 20 Ω 0 . 4 µ F 19 V S How long after the switch is closed does the voltage across the resistor drop to V resistor = 13 V? = 3 . 03592 × 10 - 6 s . 007 10.0points A long inner cylinder with radius R 1 and an outer cylindrical shell with inner radius R 2 and outer radius R 3 are concentric as shown. These cylinders extends out perpendicular to the plane shown. The charge on the inner cylinder per unit length is λ > 0 and the corresponding charge on the outer cylindri- cal shell per unit length is ( - λ/ 2) (half the magnitude and opposite in sign) . - λ/ 2
vo (jmv2332) – Extra Credit Midterm 2 – yeazell – (58010) 4 Find the magnitude of the electric field at the point a distance r from the central axis of the inner cylinder, where r > R 3 (outside both cylinders).