410.
If we
permute 7 letters of the word ‘JUSTICE’ in 7! Ways. In how many words vowels do not
come together?
A] 5040
B] 4320
C] 720
D] 120
Ans.
–
C
Vowels come together = (UIE)JSTC
Ways = 3!*5! = 720
411.
In a test called ACSAT, the average marks of 15 test takers is 240. If the marks of 5 test
takers are subtracted, the average marks decreases by 40. What are the average marks of 5 test
takers?
A] 1600
B] 320
C] 200
D] 40
Ans.
–
B
Marks of 15 test takers = 15*240 = 3600
Marks of 10 test takers = 10*200 = 2000
Marks of remaining 5 test takers = 3600
–
2000 = 1600
Average =
1600
5
= 320
412.
Simple interest on an account at 4% per annum for 13 months is more than the simple
interest on the same sum for 8 months at 6% per annum by Rs.40. What is the principal amount?
A] Rs. 3600
B] Rs. 12000
C] Rs. 4800
D] Rs. 24000
Ans.
–
B
Let principal be P.
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Acc to ques.:
P∗4∗13
100∗12
–
P
∗
6
∗
8
100
∗
12
= 40
P(
52
1200

48
1200
) = 40
P = Rs. 12000.
413.
A team uses 2 dice for deciding the person who would give a talk on “Technical aspe
cts of
effective communication”. Shalini will give a talk only if the product of 2 numbers that turn up is
greater than 20. What is the probability that Shalini would talk on the subject?
A]1/3
B] 1/9
C] 2/9
D] 1/12
E]
1/6
Ans.
–
C
Probability =
Favourable Cases
Total Cases
Total Cases = 36
Favourable Cases = (4, 5), (4, 6), (5,4), (5, 5), (5, 6), (6, 4), (6, 5), (6, 6)
Probability =
8
36
=
2
9
414.
If
10
C
x
=1, then what is the value of x if x≠0?
A] 1
B] 5
C] 10
D] 15
Ans.
–
C
n
C
r
= 1; if and only if r = 0 or n.
10
C
x
=1, x = 0 or 10.
Acc to ques.: x≠0, therefore.
x = 10
415.
A stone is dropped from a height of 5km. The distance it falls through varies directly with the
square of the time taken to fall through that distance. If it falls 64m in 4 seconds, find the distance
the stone covers in 5
th
second?
A] 36 m
B] 58 m
C] 72 m
D] 100 m
Ans.
–
D
Acc to ques.: Distance travelled = k*t
2
64 = k*4
2
k = 4
Distance travelled = 4*5
2
= 100 m
416.
A teacher can divide her class into groups of 5, 13 and 17. What is the smallest possible
strength of the class?
A] 835
B] 940
C] 1105
D] 1120
Ans.
–
C
Smallest possible class strength = LCM of 5, 13 and 17
LCM of 5, 13 and 17 = 1105
417.
Find the ratio of distances covered by a car and a cyclist when it is given that the car moves
1.5 hours at 30 kmph and the cyclist moves for 1 hour at 25kmph:
A] 6:5
B] 9:5
C] 3:2
D] 5:1
Ans
–
B
Distance covered by cyclist = 25 km; Distance covered by car = 1.5*30= 45 km
Ratio of car to cyclist = 25:45 = 5:9
418.
What is the value of log2205?
Given that log5=a, log7=b and log3=c
A] 2ba2c
B] a+2b+2c
C] 2ab+2c
D] a2b+2c
E] a+2b2c
Ans
–
B
Factorize 2205 into 3
2
*7
2
*5
Apply log both sides and put the values 2b+2c+a because log(ABC)= log A+log B + log C