d 2 h U u max h h h 3 3 h 2 h 3 3 h 2 2 h U u max 4 3 h 2 h U Hence u max 3 2 U

D 2 h u u max h h h 3 3 h 2 h 3 3 h 2 2 h u u max 4 3

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d 2 h U = u max h h ( ) [ ] h 3 3 h 2 h 3 3 h 2 2 h U = u max 4 3 h 2 h U = Hence u max 3 2 U = 3 2 2.5 × m s = u max 3.75 m s =
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