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10.0 15.0 20.0 25.0 30.0 35.0 40.0 45.0 50.0 0 5 10 15 20 25 30 35 f(x) = 0.49x + 10.83 R² = 0.45 FruitVeg5 FruitVeg5 Linear (FruitVeg5) 2. Describe an overall pattern of the data. Is there a correlation between EdCollege and FruitVeg5? What does that tell you? 020217
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Math 215 – Statistical Concepts Name: ______________________ Franklin University There is a moderate positive correlation between EdCollege and FruitVeg5 shown a correlation coefficient (r) = 0.67. This implies that the value of EdCollege and FruitVeg5 are directly proportional i.e. an increase in EdCollege leads to an increase in FruitVeg5. 3. Pick a state in this data set and use its position in the graph in question 1 to write an interpretation of what it represents and how it compares with the other states. We can use the regression line equation to predict the value of FruitVeg5 by using EdCollege. An example is Arkansas where EdCollege = 17.4 FruitVeg5 = 0.493x + 10.82 = 0.493 (17.4) + 10.82 = 19.3982 4. Can you conclude that earning a college degree will cause you to eat 5 servings of fruits and vegetables per day? Explain your answer. Yes. The coefficient of determination (R 2 = 0.447) means that 44.7 of the variance in dependent variable (FruitVeg5) is predictable from the independent variable (EdCollege) 5. Using Excel, make a scatterplot to compare the data in SmokeED (x-axis) and FruitVeg5 (y- axis) columns.Make sure you include the linear regression line on this graph. Then, cut and
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