person gets all of the questions correct by the
number of times all six questions are corrected separated by the number of times one ran the
simulation with a 80% chance.
For each single questions that's correct the total ends up to 26%
because the person is likely
to get multiple questions incorrect.

The issue is 91,15,52,41,74,5 for example 91,15,52,41,74, 5 are part of the one of the sixth
questions however it needs be repetition for the experiment that was to collect the day to analyze
the command 40 times.
To manage how many people get all of the questions correct use 1 to 10
to help 1 to 5 counting 1 t0 4 to prove the correct questions. Which is easier because it still
results in 1 to 4 is
=80%.
⅘
23) rand(Int) (1,5,6) one of the six question overlaps the overcome of 1,2,3 or 4 indicates the
question is correct another example is rand(lnt) 1 ,5,6 gives 2,2,5, 145.
25)
A)
The requirement is
to run 500 trials is one comment to pick any digit then type
command, rand(Int) (0,9,500) (STO) L1= sort Ac L1). Sto is a store key as a alphabetic
character above the period key symbolizes is a common
separator character for press
(Alpha)+ Sort A(L1 sorts the list of data in L1 into ascending order(Smaller to large).
B)
To find the Sort (A) press (STAT) (Edit) 2: sort Ac use L1 and count the number of time you
won (compare the number of times you won/500)/
There is a lucky number
the results will not change.
26)
27) you should win about 10% of the time.
32) Blood donors”
44% of the patients are type 0 Positive while the other half of the patients with type 0 blood type
is 6.8 people because you divide 44/100=11/28. Use the rand (Int)(1, 25) with 1,2,3,11 to
represent the type 0 blood type.

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- Fall '19
- Jalaya Morales