person gets all of the questions correct by the number of times all six questions are corrected separated by the number of times one ran the simulation with a 80% chance. For each single questions that's correct the total ends up to 26% because the person is likely to get multiple questions incorrect.
The issue is 91,15,52,41,74,5 for example 91,15,52,41,74, 5 are part of the one of the sixth questions however it needs be repetition for the experiment that was to collect the day to analyze the command 40 times. To manage how many people get all of the questions correct use 1 to 10 to help 1 to 5 counting 1 t0 4 to prove the correct questions. Which is easier because it still results in 1 to 4 is =80%. ⅘ 23) rand(Int) (1,5,6) one of the six question overlaps the overcome of 1,2,3 or 4 indicates the question is correct another example is rand(lnt) 1 ,5,6 gives 2,2,5, 145. 25) A) The requirement is to run 500 trials is one comment to pick any digit then type command, rand(Int) (0,9,500) (STO) L1= sort Ac L1). Sto is a store key as a alphabetic character above the period key symbolizes is a common separator character for press (Alpha)+ Sort A(L1 sorts the list of data in L1 into ascending order(Smaller to large). B) To find the Sort (A) press (STAT) (Edit) 2: sort Ac use L1 and count the number of time you won (compare the number of times you won/500)/ There is a lucky number the results will not change. 26) 27) you should win about 10% of the time. 32) Blood donors” 44% of the patients are type 0 Positive while the other half of the patients with type 0 blood type is 6.8 people because you divide 44/100=11/28. Use the rand (Int)(1, 25) with 1,2,3,11 to represent the type 0 blood type.
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- Fall '19
- Jalaya Morales