La siguiente tabla corresponde a una muestra de aleatoria de 330 clientes del

La siguiente tabla corresponde a una muestra de

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7. La siguiente tabla corresponde a una muestra de aleatoria de 330 clientes del BCP según sus ahorros mensuales en soles en el año 2018. Ahorros mensuales en soles LI LS Nº de trabajadores Fi FI {600 800) 30 30 {800 1000) 80 110 {1000 1200) 150 260 {1200 1400) 40 300 {1400 1600) 20 320 {1600 1800) 10 330 TOTAL 330 Aquí vemos que n = 330, luego n/2 = 165 110<165<260 F1<165<F2 Me= LI3+ C3 * ( 𝑁 2 −𝐹2) 𝑓3 Me=1000 + 200* (165−110) 150 Me= 1200 * 0.37 Me= 444 soles REFERENCIAS 1. Barreto, C. Estadística básica - Aplicaciones. 2a ed. Chimbote: Universidad Católica Los Ángeles de Chimbote;2008. 2. Caridad W. Guerra Bustillo, Ernesto Menéndez Acuña, and Rolando Barrero Morera. ProQuest Ebook Central - Reader [Internet]. [citado 11 de junio de 2019]. Disponible en: &query=estadistica 3. Colegio24hs. ProQuest Ebook Central - Reader [Internet]. [citado 11 de junio de 2019]. Disponible en: &query=estadistica#
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  • Fall '18
  • jose santos

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