Ms Lubna Ineirat 108 Test result Yes D No ഥ Total Positive 436

# Ms lubna ineirat 108 test result yes d no ഥ total

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Ms. Lubna Ineirat 108 Test result Yes (D) No( 𝐷 ) Total Positive 436 5 Negative 14 495 Total
3. What is the false positive. 4. What is the false negative . 5. suppose its known that the rate of disease its 11.3% find the predictive value positive. 6. suppose its known that the rate of disease its 11.3% find the predictive value negative. Ms. Lubna Ineirat 109
Chapter 5: Standard Normal distribution Properties of standard normal (Z) 1. The curve is of bell shape and symmetric about 0. 2. The area under the curve is 1. 3. Mean=median=mode=0 4. Variance=1 Ms. Lubna Ineirat 110
Ms. Lubna Ineirat 111 Using Z -table to find the area
Using Z -table to find the area Case 1: less than P(Z<1.59) P(Z<2.31) P(Z<2.08) P(Z<0.07) P(Z<3) P(Z<0) P(Z<3.86) P(Z<5) P(Z<8) Ms. Lubna Ineirat 112
Ms. Lubna Ineirat 113 Find the following: P(Z<-1.39) P(Z<-2.31) P(Z<-0.05) P(Z<-2.06) P(Z<-1.5) P(Z<-0.8) P(Z<-0.24) P(Z<-4) P(Z<-3.45) P(Z<-6) P(Z<-11)
Case 2: more than Ms. Lubna Ineirat 114 P(Z>1.59) P(Z>2.31) P(Z>1.08) P(Z>0.07) P(Z>2.3) P(Z>0.57) P(Z>3) P(Z>0) P(Z>3.86) P(Z>5) P(Z>8)
Ms. Lubna Ineirat 115 Find the following P(Z>-3.59) P(Z>-1.51) P(Z>-2.02) P(Z>-0.04) P(Z>-6.2) P(Z>-0.87) P(Z>-3) P(Z>-3.86) P(Z>-5) P(Z>-7)
Case 3: more than & less than (between) P(1.54< Z< 2.39) --------------------------- P(0< Z <3.49) ------------------------- P(2.56 < Z< 3.12) -------------------------- P(-1.54< Z < 2.39) Ms. Lubna Ineirat 116
Find the value of c if Case 1: less than P(Z<c)=0.8413 P(Z<c)=0.9793 P(Z<c)=0.9934 P(Z<c)=0.8213) Ms. Lubna Ineirat 117
Find the value of c if P(Z<c)=0.0022 P(Z<c)=0.0158 P(Z<c)=0.1711 P(Z<c)=0.1210) P(Z<c)=0.9726 Ms. Lubna Ineirat 118
Find the value of c Case 2: more than P(Z>c)=0.9821 P(Z>c)=0.9948 P(Z>c)=0.0030 P(Z>c)=0.9251 P(Z>c)=0.505 Ms. Lubna Ineirat 119
Find the value of c Case 3: (between) P(c<Z>0)=0.1700 P(0<Z>c)=0.4983 P(c<Z>3.54)=0.994530 P(-2.53<Z>c)=0.9934 Ms. Lubna Ineirat 120
Not Standard Normal Let X be a normal with mean μ and variance 𝜎 2 (X:N( μ , 𝜎 2 )) Then Z= 𝑋−𝜇 𝜎 is standard normal, then Z= 𝑋−𝜇 𝜎 is N(0,1) Not standard Ms. Lubna Ineirat 121
Example : if mean =50, variance=100 find the following: 1. P(X<60) 2. P(X<30) 3. P(X<90) 4. P(X>300 5. P(X>70) 6. P(X>20) 7. P(X>90) 8. P(50<X<65) 9. P(30<X<55) 10. P(X=70) 11. P(X=30) Ms. Lubna Ineirat 122
12. Find 𝑃 67 13. Find 𝑃 33 14. Find 𝑃 75 Ms. Lubna Ineirat 123

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