All the confidence intervals contain the value zero

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All the confidence intervals contain the value zero, thus indicating that we cannot conclude the means differ at the5% significance level.
c.The Tukey’s HSD approach is preferred over Fisher’s because it reduces the probability of Type I error (thelikelihood of incorrectly rejecting the null hypothesis).Given the following information, construct an ANOVA table. UseTable 4.(Round intermediate values to 4 decimal placesand your answers except "df" to 2 decimal places.)ANOVASource of VariationSSdfMSFF critat 5%Between GroupsWithin GroupsTotalb.At the 5% significance level, what is the conclusion to the test?11.3433.78 ± 0.013.58 ± 0.052.77 ± 0.0159.13561.06 ± 0.0170.4759
rev: 08_25_2013_QC_34000Explanation:Atα =0.05,=F0.05,(3,56)= 2.77. SinceF(3,56)= 3.58 > 2.77,we rejectH0. At the 5% significance level, we can conclude that the population means are not all equal.
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Term
Spring
Professor
Professor Liu Chiang
Tags
Statistical hypothesis testing