The broadcast address of the subnet is 10163255

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4. The broadcast address of the subnet is 10.16.3.255 255.255.254.0. a) 1 and 3b) 2 and 4c) 1, 2 and 4d) 2, 3 and 4View AnswerAnswer: bExplanation: The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 – 254). So this makes the subnets in the interesting octet 0, 2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0subnet. The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid hostaddresses are 2.1 through 3.254. 4. What is the maximum number of IP addresses that can be assigned to hosts on a local subnet that uses the 255.255.255.224 subnet mask? 5. You need to subnet a network that has 5 subnets, each with at least 16 hosts. Wohich classful subnet mask would you use
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6. You have a network that needs 29 subnets while maximizing the number of host addresses available on each subnet. How many bits must you borrow from the host field to provide the correct subnet mask? 7. If an Ethernet port on a router were assigned an IP address of 172.16.112.1/25, what would be the valid subnet address of this host? a) 172.16.112.0b) 172.16.0.0c) 172.16.96.0d) 172.16.255.0View AnswerAnswer: aExplanation: A /25 mask is 255.255.255.128. Used with a Class B network, the third and fourth octets are used for subnetting with a total of 9 subnet bits, 8 bits in the third octet and 1 bit in the fourth octet. Since there is only 1 bit in the fourth octet, the bit is either off or on-which is a valueof 0 or 128. The host in the question is in the 0 subnet, which has a broadcast address of 127 since 128 is 8. You have an interface on a router with the IP address of 192.168.192.10/29. Including the router interface, how many hosts can have IP addresses on the LAN attached to the router interface?
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