RESULTS 11 Graph showing the pressure atm in function of the volume mL Volume

# Results 11 graph showing the pressure atm in function

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RESULTS: 1.1 Graph showing the pressure (atm) in function of the volume (mL). Volume (mL) Pressure (atm) K value 55.0 0.9761 0.0177 50.0 1.0644 0.0213 45.0 1.1804 0.0262 40.0 1.3180 0.0330 35.0 1.5084 0.0431 30.0 1.7326 0.0578 1.2 Values for the first experiment. Mean Standard Deviation Standard Deviation of the Mean Confidence Interval (CI) 0.0332 0.0151 0.00616 0.0332 ±(0.0151) 1.3 Statistical analysis results for the firs experiment. 2.1 Graph showing the pressure (atm) in function of the temperature (K). Pressure (atm) Temperature (K) K value 0.9744 274.9 0.00354 1.0063 284.3 0.00354 1.0389 294.6 0.00253 1.0730 304.8 0.00352 1.1072 314.2 0.00352 2.2 Values obtained for the second experiment. Mean Standard Deviation Standard Deviation of the Mean Confidence Interval (CI) 0.0353 1.055x10^-5 4.718x10^-6 0.00353 ±(1.212x10^-5) 2.3 Statistical analysis results for the second experiment. 3.1 Graph showing the volume(mL) in function of the temperature(K) Temperature (K) Volume (mL) K value 283.3 0.00 0 292.6 3.10 0.0106 303.4 6.90 0.0227 312.1 11.5 0.0368 321.7 15.0 0.0466 3.2 Values obtained for the third experiment. Mean Standard Deviation Standard Deviation of the Mean Confidence Interval (CI) 0.0233 0.0189 0.00616 0.0233 ±(0.0217) 3.3 Statistical analysis results for the third experiment. Graph 1.1 shows the linear fit, the proportionality between pressure and volume. This plot gave us the relationship between pressure and volume: P=mV (m being the slope). Table 1.2 shows the experimental values of the pressure and volume. The table also shows the k values calculated using the information obtained in graph 1.1 (we notice that the k values are close to each other). Table 1.3 shows the statistical analysis. The statistical analysis calculations allow us to know if the m is statistically equal to the k values calculated. The calculation that really allows proving it is the confidence interval (CI). For this first experiment, m is not in the confidence interval so m and k can’t be considered statistically the same. Graph 2.1 also shows the linear fit, but this time between pressure and temperature. This plot also gave us the relationship between pressure and temperature: P=mT (m being the slope). Table 2.2 shows the experimental values of the pressure and temperature. The table also shows the k values calculated using the information obtained in graph 2.1(we notice that the k values are also close to each other). Table 2.3 shows the statistical analysis for the second experiment. The objective of these is the same as for the first experiment. For this experiment, m is also in the confidence interval; m is then considered statistically the same as the k values calculated. Graph 3.1 shows the linear fit between the volume and temperature. This plot gave us the relationship: V=mT (m being the slope). Table 3.2 shows the experimental values of the volume and temperature. The last column shows the k values calculated using the information obtained in the graph 3.1. Table 3.3 shows the statistical analysis for the third experiment. The objective of these is the same as for the first in second experiments. For this experiment, as the previous experiment, m is in the confidence interval; m is then considered statistically the same as the k values calculated. DISCUSSION: The main objective of this experiment was to confirm the three hypotheses stated at the beginning of the experiment. The three hypotheses were stated were:  #### You've reached the end of your free preview.

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