V KMnO 4 solution 02 M Grams Fe 2 salt 6081 6046 Initial Buret Reading 660 2359

# V kmno 4 solution 02 m grams fe 2 salt 6081 6046

This preview shows page 3 - 5 out of 5 pages.

V. KMnO4solution: .02 M
Grams Fe2+salt.6081.6046Initial Buret Reading6.6023.59Final Buret Reading23.5938.60mL MnO4-Solution16.9915.01Moles Fe2+.01089.01083Moles MnO4-3.398x10-43.002x10-4Moles MnO4-: .01699 L MnO4-x .02 moles=3.398x10-4moles MnO4-1 LMoles Fe2+:.6081 grams Fe2+x 1 mole__= .01089 moles Fe2+155.85 gramsVI. A.Based on the data collected in part V, the Fe2+reacts with MnO4-in a 30:1 ratio rather than a 5:1 ratio as shown in the equation from II.C.New equation:30 Fe2+(aq) + MnO4-(aq) →Fe3+(aq) + Mn2+(aq)Oxidation Rxn: 30Fe2+→ 30Fe3+Reduction Rxn: MnO4-Mn2+Step Two:SkipStep Three: MnO4-→ Mn2++ 4H2OStep Four: MnO4-+ 8H+→ Mn2++ 4H2O
Step Five, Six, and Seven:30Fe2+→ 30Fe3++ 30e-6[MnO4-+ 8H++ 5e-→ Mn2++ 4H2O]30Fe2+(aq)+ 6MnO4-(aq)+48H+30Fe3+(aq) + 6Mn2+(aq)+ 24H2O(l)

#### You've reached the end of your free preview.

Want to read all 5 pages?

• Spring '16
• Christine Gaudinski

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern