CHE4284_5292_Problems_20130520_Solution

How many industrial related deaths are expected each

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A plant employs 1500 full time workers in a process with a FAR of 5. How many industrial related deaths are expected each year? Solution: FAR = 5 This means 5 deaths per year per 10 8 hours exposure. The Fatal Accident Rate is based on 2000 hours/worker. Total working hours per year = 1500 workers 2000 hours = 3 x 10 6 hours 1 worker Total working hours per year = 3 x 10 6 hours Deaths per year = 3 x 10 6 hours 5 deaths = 0.15 deaths 10 8 hours This means that 1 death is expected every 6.6 years. (6.6 x 0.15 1)
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CHE-4284/CHE-5292 Industrial Safety Summer 2013 Problems MEPdeF - 05/20/2013 Problem 4: The airline industry claims commercial airline transport has fewer deaths per mile than any other means of transportation. Do the accidents statistics support this claim? In 1984 the airline industry posted 4 deaths per ten-million passenger miles. What additional information is required to compute a FAR? A fatality rate? Solution: Claim: Commercial Airline has fewer deaths per mile than any other means of transportation. From Table 1-4 get FAR for other types of transportation. Ex: Car – FAR = 57 Bicycle – FAR = 96 Airline – FAR = 240 Due to the high speed of the aircraft, more miles are accumulated. On a “per hour” basis, traveling by plane is approximately 4 times more dangerous than traveling by car. (240/57 = 4) FAR Computation : Need total hours exposed. Assume aircraft average speed. Average speed = 250 miles/hour. Total hours exposed = 10 x 10 6 miles = 40,000 hours 250 miles/hour FAR = 4 deaths 10 8 hours = 10,000 40,000 hours 10,000 is larger than the 240 reported in Table 1-4. Calculating a fatality rate will require the total number of passengers in the ten-million passenger miles. Assume that on average a person traveled 350 miles. Total passengers = 10 x 10 6 miles 1 person = 28,570 persons 350 miles Fatality Rate = 4/28,570 = 1.4 x 10 -4 (high value)
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