Additionally as methanol is a protic solvent hydrogen

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Additionally, as methanol is a protic solvent, hydrogen bonding will occur in the liquid phase that is not present in the gas phase, leading to a negative enthalpy for the process. Calculate S°, H°, and G° for the phase change of CH 3 OH( g ) to CH 3 OH( l ) at 298 K. (e) With the information in parts (b), (c) and (d), a thermodynamic cycle at 298 K can be completed. Complete the thermodynamic cycle by providing all values of G°, H°, and S°. H 2 CO ( g ) + H 2 ( g ) H 3 COH ( g ) G° = H° = S° = H 3 COH ( l ) G° = H° = S° = 298 K G° = H° = S° = Chem 33, Kanan & Stack, 2012, PS 5; pg 4
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4. Construct a reaction coordinate diagram for the reaction (A-->C) in which the relative stabilities of the species are C > A > B and for which the relative order of the four rate constants is k –1 > k 2 > k 1 >> k –2 . A B C k 1 k 2 k 1 k –2 reaction coordinate free energy (a) Which is the rate-determining step in your diagram? (b) How many intermediates are in this reaction? (c) How many transition states are in this reaction? (d) Is the reaction endergonic or exergonic? (e) Of the two forward steps, which has the faster rate? (f) What is the relative order of the four free energies of activation, G ? Chem 33, Kanan & Stack, 2012, PS 5; pg 5
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5. The difference in the standard free energies of formation ( ∆∆ G f °) for 1-butene and 2-methylpropylene is 3.2 kcal mol -1 . (a) Which compound is more stable? (b) The standard free energies of activation ( G ) for the acid catalyzed hydration of 2-methylpropylene and 1-butene (a net addition of water across a double bond to give a saturated alcohol) are 19.0 and 23.2 kcal mol -1 , respectively.
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