[复变函数与积分变换].焦红伟&尹景本.文字版.PDF.pdf

# F t t δ 14 1 1 sin sin 2 3 6 f t t t 15 2 e e t t f

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f t t δ = (14) 1 1 ( ) sin sin 2 3 6 f t t t = (15) 2 e e ( ) t t f t t = (16) 1 ( ) e (sin cos ) 2 t f t t t t = (17) ( ) 5sin 2 cos2 f t t t = 7 (1) 3 1 ( ) [(7 2 )e 3e ] 4 t t y t t = + (2) 2 ( 1) 2( 1) 1 1 ( ) e e [ e e ] ( 1) 2 2 t t t t y t u t = + − + + (3) ( ) 2sin cos2 y t t t = − (4) ( ) e sin t y t t t = (5) 2 1 1 1 ( ) e sin 2 10 5 t y t t = − + (6) 1 ( ) sin 2 y t t t = 8 2 2 2 2 2(3 12 13) ( ) [( 3) 4] s s F s s s + + = + + 9 3 ( ) 6 t f t a t = + 10 ．解：设 [ y ( t ) ]＝ Y ( s ) ，对方程两边同取拉氏变换．并考虑到初始条件，得到

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• Winter '16
• Gilles Lamothe

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