B haley is incorrect the bases differ 1 70 a not in

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b:Haley is incorrect.The bases differ.1-70.a:Not in scientific notation because 62.5 should be 6.25.6.25×104.b:Not in scientific notation because 1000 should be103and it uses a” instead of an”.6.57×103.c:Not in scientific notation because 0.39 should be 3.9.3.9×1081-71.a:12b:18c:211-72.a:x= –2b:x=112c:x= 0d:no solution×
6© 2014 CPM Educational Program. All rights reserved.Core Connections Integrated ILesson 1.3.21-81.a:14b:1c:152=125d:1x21-83.a - c:(a) and (b) are functions because each only has one output for each input.d:a: D: all real numbers, R:1y3;b: D: all real numbers, R:y0;c: D:x≥ −2, R: all real numbers1-84.a:1.6×108b:5.8413×10101-85.The unshaded triangle is half the area of the rectangle (0.5(8)(17) = 68 sq. in.), so theshaded area is the other half.Lesson 2.1.12-6.y=7x+52-7.27b3a62-8.a:2b:–4c:–5, –2, 0, 2, 4d:–2e:132-9.a:60b:127c:02-10.See solutions on the diagram at right.74°74°106°106°74°74°106°106°1-82.a: x=2b:x=53
Selected Answers© 2014 CPM Educational Program. All rights reserved.7Lesson 2.1.22-18.ΔyΔx=132-19.The equation in part (b) has no solution.Possible reason: There are the same number ofx-terms on each side of the equation, so if you try to solve, you end up with an equationsuch as 11 = 4, which is impossible.2-20.a:–10b:–4c:undefinedd:2232-21.No solution; you cannot divide by 0.2-22.a:23865b:3718c:518d:613Lesson 2.1.32-30.a:Linea:y= 2x– 2,Lineb:y= 2x+ 3b:It would lie between linesaandb, because itsy-intercept is at (0, 1).c:It would slant downward but would have the samey-intercept as the line from part (b).2-31.See graph at right.Approximately 79%2-32.a:2.4×108b:1.4×109c:2.2.5×1022-33.a:–15xb:64p6q3c:3m82-34.Graphs (a) and (b) have a domain of all real numbers,while graphs (a) and (c) have a range of all real numbers.Graphs (a) and (b) are functions.607080901000 1 2 3 4 5 6Final %AP Score
8© 2014 CPM Educational Program. All rights reserved.Core Connections Integrated ILesson 2.1.42-40.a:m=53,b= (0, –4)b:m=47,b= (0, 3)c:m= 0,b= (0, –5)2-41.a:m=–2b:m= 0.5c:undefinedd:m= 02-42.a:correctb:7.89×104c:3.15×103d:correct2-43.a:4b:16c:y=4x+16d:It would get steeper.2-44.a:While walking double (or triple) the distance, they would encounter double (or triple)the number of dogs. If they walked zero blocks, they would encounter zero dogs.Thedogs in the area are evenly spread out along the blocks.b:17 dogs12 blocks=xdogs26 blocks;x36.83 so 37 dogs would be reasonable.c:1.42 dogs per blockLesson 2.2.12-47.A very strong positive nonlinear association with no apparent outliers.2-48.See graph at right.The number of people must be wholenumbers, and Mikko probably did not keep track of parts ofburgers, so the points should not be connected; that is, there isno possible data between the points. If a line is drawnto model the trend, it should be straight rather than go throughall the points.

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