The Arithmetic mean of the sequence Median of the sequence Therefore AM 2n 2

The arithmetic mean of the sequence median of the

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The Arithmetic mean of the sequence = Median of the sequence.Therefore, A.M = 2n + 2GRE QUANT DATABASE(UPDATED TILL December 10th) updated by Saranya1)Given that, the probability that it won't rain tomorrow is 0.46Col A: The probability that it will rain tomorrow at temperature of 85degree centigradeCol B: 0.54Solution:p is the probability of success (probability that it will rain.)q is the probability of failure (probability that it won't rain.)then p + q = 1. Given :q = 0.46 Therefore, p = 1 – 0.46 = 0.54 2) If 'N' is a 3 digit number where hundreds place is 'x' and units place is 'y' then what will be the factor for N-100x-y?A. 3 B. 4 C. 5 D. 6 E. 7 Solution:Case 1 : Let us take N as 131, x = 1 and y = 1,then , N-100x-y = 131 – 100-1= 30, which is a factor of 3, 5 and 6.Case 2 : Let us take N as 456, x=4 and y = 6then, N-100x-y = 456 – 400 – 6 = 50 , which is a factor of 5Case 3 : Let us take N as 142, x=1and y = 2then, N-100x-y = 142 – 100 – 2 = 40 , which is a factor of 4 and 5.From all these cases, what we infer is, for any number of N, the factor for N-100x-y will be 5.Answer is Option C (5)
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3) If 'S' is a set of all integers that are multiples of 3 & multiples of 5, provided it should be of 2 digits, then find the range of S?A. 81 B. 77 C. 87 D. 89 E. 91 Solution:Multiples of 3 and Multiples of 5 ( condition : it should be of 2 digits)Multiples of 3 = { 12 , 15 , 18 , 21 ,........................., 99}Multiples of 5 = { 10, 15, 20, 25, .............................,95}Therefore, S = { 10,12,15,18,...........................99}Range = Maximum number – Minimum NumberRange of S = 99 – 10 = 89Answer : Option D (89) 4) Find the number of possible values of x & y in the expression (5+x)/(7+y), so that the resultant ratio is 5:7 where x and y lie between 12 and 29?Solution:(5+x)/(7+y) = 5/7x and y should lie between 12 and 29To Find :x and y5+x must be a multiple of 5 , the possible values will be (5+0), (5+5), (5+10), (5+15),(5+20),(5+25), (5+30),..................7+y must be a multiple of 7 , the possible values will be (7+0), (7+7), (7+14), (7+21),(7+28),(7+35), (7+42),..................(5+x)/(7+y) can be (5+0)/(7+0) , (5+5)/(7+7), (5+10)/(7+14), (5+15)/(7+21) , (5+20)/(7+28) , (5+25)/(7+35) , (5+30)/(7+42)All the above said are possible values that x and y can take, butthe condition given is x and y should lie between 12 and 29.So , eliminating options, which does not lie in this range, we get(5+15)/(7+21) and (5+20)/(7+28).Answer : x = 15 and y = 21 (or) x = 20 and y = 28Whichever option given in the question can be marked as the answer.5) If -2 < x < -1, thenCol A: 1/x3Col B: 1/xSolution:
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In all cases except x = -1 , thevalue of 1/x3 > value of 1/xAnswer : Option A (Column A is greater)Note : If the question given as If 2 < x < 1 , all positive values, thenIn all cases except x = 1Value of 1/x3 < value of 1/x.GRE QUANT DATABASE(UPDATED TILL December 9th) updated by Saranya1) A triangle ABC is given, in which lengths of two sides were given as BC = 12 , AC = 13 and the perimeter of the triangle is 32. Col A: Measure of angle of B Col B: 90Solution:AB + BC + AC = 32BC and AC are given as 12 and 13 , therefore, AB = 7Note : Conditions to satisfy If angle B to be Right angle Condition to be satisfiedAB2+ BC2= AC2If angle B to be an Obtuse angle Condition to be satisfiedAB2+ BC2< AC2If angle B to be an Acute angleCondition to be satisfiedAB2+ BC2> AC2In this question , if we solve the values we will get as AB2+ BC2> AC272 + 122> 132, therefore, it is an acute angleAnswer : Option B ( Column B is greater )
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