Homework4_Solution (1).docx

2148 ev b f c g f e e e e e 90518 2148 12 1 ev c kt e

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2148 . 0 eV (b) F c g F E E E E E 90518 . 0 2148 . 0 12 . 1 eV (c) kT E E N p F o exp  0259 . 0 90518 . 0 exp 10 04 . 1 19 3 10 90 . 6 cm 3 (d) Holes (e) i o Fi F n n kT E E ln 10 15 10 5 . 1 10 7 ln 0259 . 0 338 . 0 eV 5. (a) o F p N kT E E ln 15 19 10 5 10 04 . 1 ln 0259 . 0 1979 . 0 eV (b) E E E E E F g F c 92212 . 0 19788 . 0 12 . 1 eV (c)  0259 . 0 92212 . 0 exp 10 8 . 2 19 o n

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3 10 66 . 9 cm 3 (d) Holes (e) i o F Fi n p kT E E ln 10 15 10 5 . 1 10 5 ln 0259 . 0 3294 . 0 eV 6. 034533 . 0 300 400 0259 . 0 kT eV 2 / 3 19 300 400 10 04 . 1 N 19 10 601 . 1 cm 3 2 / 3 19 300 400 10 8 . 2 c N 19 10 3109 . 4 cm 3  19 19 2 10 601 . 1 10 3109 . 4 i n 034533 . 0 12 . 1 exp 24 10 6702 . 5 12 10 381 . 2 i n cm 3 (a) o F p N kT E E ln 15 19 10 5 10 601 . 1 ln 034533 . 0 2787 . 0 eV (b) 84127 . 0 27873 . 0 12 . 1 F c E E eV (c)  034533 . 0 84127 . 0 exp 10 3109 . 4 19 o n 9 10 134 . 1 cm 3 (d) Holes (e) i o F Fi n p kT E E ln
12 15 10 381 . 2 10 5 ln 034533 . 0
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