Unformatted text preview: Equal variances: not met, as said earlier. Normality: may be. Even though the normal scores plot is not linear, its shape might be only explained by the rhubarb’s large SD. (c) dfCultivar is 5 1 = 4 and dfError is 35 so the pvalue is < . 001. Strong evidence that the 5 oca cultivars do not all have the same mean oxalate content. (d) For α = 0 . 01 we get Q = 5 . 05 at df=30 and 4.93 at df=40. Our dfError=35. We prefer being conservative and use Q = 5 . 0, close to the Q value at df=30.(The true value is Q = 4 . 98 at dfError= 35). The critical distance is the d Q = 5 . p 3251 * 1 / 8 = 100 . 8. Only cultivar O2 is signifi cantly different from all other oca cultivars. O1 O4 O3 O5 O2 306 336 397 403 539 5. (a) False. The equality is always valid, even when X and Y are dependent. (b) True. The median depends on middle values only, not on the largest or on the lowest values. The mean depends on all values and can be pulled by outliers. (c) False. The tdistribution is symmetric, the Fdistribution is not. (d) False. The Binomial can be skewed, but never bimodal. (e) True. The ttest depends on means, which are affected by outliers. The MannWhitney test depends on ranks only, not affected by extreme values. 1...
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 Fall '08
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 Normal Distribution, OCA, Normal scores plot, oca cultivars, female’s weight

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