Excitation table q clk j k j k qt1 qt 0 0 1 1 1 1 qt

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Excitation Table Q clk J K J K Q(t+1) Q(t) 0 0 0 1 1 0 1 1 Q(t) 0 1 Inputs 0 0 0 1 1 0 1 1 Q(t+1) Q(t) X 0 J K 0 X 1 X X 1 Q D clk Q(t+1) D 0 0 1 1 Inputs 0 0 0 1 1 0 1 1 Q(t+1) Q(t) D 0 1 0 1
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1/0 1/1 0/0 0/0 S 0 S 1 Next State logic CC-2 D Q clk z CC-1 Output logic x Present State Input Next State x 0 1 State Transition Table Q(t+1) Q(t) 1 1 z Output D 0 1 0 0 0 1 1 0 0 0 0 1 0 0 1 1
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1/0 1/1 0/0 0/0 S 0 S 1 Next State logic CC-2 D Q clk z CC-1 Output logic x Present State Input Next State x 0 1 State Transition Table Q(t+1) Q(t) 1 1 z Output D 0 1 0 0 0 1 1 0 0 0 0 1 0 0 1 1 . . ; . D Q x Q x z Q x
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1/0 1/1 0/0 0/0 S 0 S 1 Next State logic CC-2 D Q clk z CC-1 Output logic x Present State Input Next State x 0 1 State Transition Table Q(t+1) Q(t) 1 1 z Output D 0 1 0 0 0 1 1 0 0 0 0 1 0 0 1 1 . . ; . D Q x Q x z Q x D Q clk x z
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Example-2 1/0 1/1 0/0 0/0 S 0 S 1 Memory (FFs) y z Next State logic Output logic x CC-2 CC-1 Y clk
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Example-2 1/0 1/1 0/0 0/0 S 0 S 1 Memory (FFs) y z Next State logic Output logic x CC-2 CC-1 Y clk 1. How many FFs do we need? 2. Which FF do we choose? 3. How are the states encoded?
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Example-2 1/0 1/1 0/0 0/0 S 0 S 1 Memory (FFs) y z Next State logic Output logic x CC-2 CC-1 Y clk 1. How many FFs do we need? 1 2. Which FF do we choose? Say JK FF 3. How are the states encoded? Say FF output Q=0 represents S 0 and Q=1 represents S 1 state
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1/0 1/1 0/0 0/0 S 0 S 1 Next State logic CC-2 z CC-1 Output logic x clk J K Q Q
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1/0 1/1 0/0 0/0 S 0 S 1 Next State logic CC-2 z CC-1 Output logic x clk J K Q Q Present State Input Next State x 0 1 State Transition Table Q(t+1) Q(t) 1 1 z Output 0 1 0 0 0 1 1 0 0 0 0 1 J K
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1/0 1/1 0/0 0/0 S 0 S 1 Next State logic CC-2 z CC-1 Output logic x clk J K Q Q Present State Input Next State x 0 1 State Transition Table Q(t+1) Q(t) 1 1 z Output 0 1 0 0 0 1 1 0 0 0 0 1 J K 0 0 1 1 0 1 1 Q(t+1) Q(t) 0 J K 0 X 1 X X 1 X 0
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1/0 1/1 0/0 0/0 S 0 S 1 Next State logic CC-2 z CC-1 Output logic x clk J K Q Q Present State Input Next State x 0 1 State Transition Table Q(t+1) Q(t) 1 1 z Output 0 1 0 0 0 1 1 0 0 0 0 1 J K X 1 0 X 1 X X 0 0 0 1 1 0 1 1 Q(t+1) Q(t) 0 J K 0 X 1 X X 1 X 0
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1/0 1/1 0/0 0/0 S 0 S 1 Next State logic CC-2 z CC-1 Output logic x clk J K Q Q Present State Input Next State x 0 1 State Transition Table Q(t+1) Q(t) 1 1 z Output 0 1 0 0 0 1 1 0 0 0 0 1 J K X 1 0 X 1 X X 0 ; ; . J x K x z Q x 0 0 1 1 0 1 1 Q(t+1) Q(t) 0 J K 0 X 1 X X 1 X 0
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1/0 1/1 0/0 0/0 S 0 S 1 Next State logic CC-2 z CC-1 Output logic x clk J K Q Q Present State Input Next State x 0 1 State Transition Table Q(t+1) Q(t) 1 1 z Output 0 1 0 0 0 1 1 0 0 0 0 1 J K X 1 0 X 1 X X 0 ; ; . J x K x z Q x Q clk x J K z 0 0 1 1 0 1 1 Q(t+1) Q(t) 0 J K 0 X 1 X X 1 X 0
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Example-3 S 0 S 2 S 3 S 1 1 1 0 0 0 0 1 1
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Example-3 S 0 S 2 S 3 S 1 1 1 0 0 0 0 1 1 For 4 states a minimum of two FFs will be required. Let us choose 2 D FFs A &B
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Example-3 S 0 S 2 S 3 S 1 1 1 0 0 0 0 1 1 For 4 states a minimum of two FFs will be required. Let us choose 2 D FFs A &B A B FF O/P S 0 S 1 S 2 S 3 State 0 0 1 0 0 1 1 1
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