notebook for an outline of the general procedure The molarity of the NaOH was

Notebook for an outline of the general procedure the

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notebook for an outline of the general procedure. The molarity of the NaOH was 0.09067 M and the Unknown Acid used was “3225”. Chem 201, Experiment 4 Titration Curves
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Procedure: See pre-lab on page of my laboratory notebook for the outline of the general procedure. The molarity of the NaOH was .09231 M. The number of the unknown acid that was used was 3547. Experimental Data: See titration curve in the second to last page. Calculated Results: Initial volume: 14.80 Final volume: 38.00 Volume needed for equivalent point: 23.20 Concentration of acid: 0.0857 M K a from initial pH: 2.17x10 -4 Titration Point volume pH [base]/[acid] pK a K a ¼ 20.6 2.35 .33 2.83 1.47x10 -3 ½ 26.4 2.36 1 2.36 4.37x10 -3 ¾ 32.2 2.36 3 1.88 1.32x10 -2 Average - - - 2.36 6.34x10 -3 Sample Calculations: See last page in lab-report for sample calculations. Discussion: In this experiment my concentration for the titrated acid was 8.57x10 -2 when 23.20 ml were titrated. My calculated K a value at the pH of 2.36 (initial pH) was 2.17x10 -4 . The calculated pK a values were 1.47x10 -3 , 4.37x10 -3 , and 1.32x10 -2 having an average of 6.34x10 -3 . Some sources of error could have been that we didn’t use the pipette correctly and therefore our volume could have affected the calculations. Another source of error could be reading the burette wrong and therefore not having the correct volumes would cause the concentrations to be off. Chem 201, Experiment 4 Titration Curves
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Procedure See the pre-lab report on page 39 of my laboratory notebook for an outline of the general procedure. The molarity of the NaOH was 0.09067 M and the Unknown Acid used
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