83 cm for n 1 The percent error between this value and the measured d 2 is 263

83 cm for n 1 the percent error between this value

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is found to be 3.83 cm for n = 1. The percent error between this value and the measured d 2 is 26.3%. These errors can be attributed to incidental table shaking, imprecise 2-4° angle increments, averaging the voltmeter, and non-uniformity within the pseudo-crystalline structure. d 1 d 2 d 3
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Physics 1600 with Richard Capobianco - Bragg Scattering 3 EXPERIMENT 1 θ (°) Volts (V) 0 1.76 2 1.53 4 2.64 6 2.82 8 2.09 10 0.88 12 0.52 14 0.34 16 0.31 18 0.39 20 0.22 22 0.79 24 0.5 26 0.202 28 0.42 30 0.016 32 0.121 34 0.14 36 0.123 38 0.05 40 0.311 42 0.439 44 0.311
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Physics 1600 with Richard Capobianco - Bragg Scattering 4 46 0.392 48 0.122 50 0.054 and EXPERIMENT 2 θ (°) Volts (V0 0 2.5 2 2.135 4 1.64 6 1.495
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Physics 1600 with Richard Capobianco - Bragg Scattering 5 8 1.178 10 1.06 12 0.685 14 0.486 16 0.167 18 0.09 20 0.64 22 0.77 24 0.44 26 0.151 28 0.272 30 0.55 32 0.67 34 0.55 36 0.33 38 0.48 40 0.43 42 0.31 44 0.41 46 0.62 48 0.75 50 0.58
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Physics 1600 with Richard Capobianco - Bragg Scattering 6 Answers 1) Give Two additional examples of sets of Bragg planes that could be probed in theory. Draw a diagram of the Bragg planes in the crystal lattice and label the distance, d .
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Physics 1600 with Richard Capobianco - Bragg Scattering 7 2) Suppose you did not know beforehand the orientation of the inter-atomic planes in the crystal. How would this affect the complexity of the experiment? Which measurements should you take? The experiment would proceed as normal, with the exception being that the “atom” locations are not known. The intensity of light corresponds to a certain wavelength, and that wavelength corresponds to a distance. This distance can show the spacing of atoms, generally in Angstroms, and from there, atomic bonds can be found.
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  • Fall '12
  • BorisSinkovic
  • Diffraction, Crystal, Crystallographic database, Bragg scattering

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