Seeing that the t value for the multimeter is smaller

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Seeing that the t-value for the multimeter is smaller, we can say that in this case the multimeter is more accurate than the Wheatstone. Conclusion: In the Wheatstone section of the experiment, we had to find the value of an unknown resistance and compare it to the actual value which is about 150Ω. After plugging in the value obtained for R B from the Wheatstone into the proportion equation, I found that the resistance for
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the unknown is 145.9 ± 0.1 Ω. During the lab, we were told that the actual value of the unknown was around 150 Ω therefore: This value shows that the value obtained from the Wheatstone was acceptable because in general the t-value should be 1 and this value is fairly close to 1. In addition since the t-value from the multimeter was smaller, it means that the multimeter measured a more accurate value of resistance for the unknown resistor. Lastly for this experiment, one source of error that we had was our wires. We encountered problems connecting our wires to make it longer in order to reach the battery and in the process the wires would sometimes disconnect or they would touch the other wires and because of that we thought that it somehow affected the measurements that we recorded. One way this source of error could be improved is by using alligator clips to connect the wires and it also holds the wires much better and prevents disconnection. 2CL Experiment 3 Worksheet: 1. (Section 4) How is this case different from the previous? How much current is coming from each of the batteries? Even though both circuits contain the same number of batteries which circuit would drain the batteries more quickly? The light bulb connected with two batteries in parallel is dimmer than the light bulb where the set up had two batteries in series. This case is different from the previous because now that the batteries are connected in parallel, the current coming from each of the batteries has to travel through the path leading to the light bulb and the path leading to the other battery therefore the current is split in half. Thus, only half of the current is coming from each battery.
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