8.–/1 pointsHoltLinAlg1 6.1.037.Determine if the statement is true or false, and justify your answer.An eigenvalueλmust be nonzero, but an eigenvectorucan be equal to the zero vector.
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9.–/1 pointsHoltLinAlg1 6.1.039.Determine if the statement is true or false, and justify your answer.Ifuis a nonzero eigenvector ofA, thenuandAupoint in the same direction.True. Sinceuis a nonzero eigenvector ofA, there existsλ> 0 such thatAu=True. Sinceuis a nonzero eigenvector ofA, there existsλ< 0 such thatAu=False.Auanduare perpendicular.False. Ifλ< 0, thenAuandupoint in opposite directions.False. Ifλ> 0, thenAuandupoint in opposite directions.λ< 0,A=−1 00 0u=,10Au=−uandλu.λu..
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