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Test Stat = You will need to use all 16 Count values but I am only showing you the first and last value because there
isn't room to write out the entire equation.Question 12 of 201.0/ 1.0 PointsClick to see additional instructionsA high school runs a survey asking students if they participate in sports. The results are found below. Run an independence test for the data atα=0.01.FreshmenSophomoresJuniorsSeniorsYes75885542No30283840Enter the test statistic - round to 4 decimal places.16.2406Answer Key:16.2406Feedback:We are running a Chi-Square Test for Independence. Copy and Paste the table into Excel. You are given the Observed Counts in the table. Next you need to sum the rows and columns. Once you have those you need to calculate the Expected Counts. You need to find the probability of the row and then multiple it by the column total.FreshmenSophomoresJuniorsYes758855No302838Sum105116FreshmenSophomoresJuniorsYes=105*(260/396)=116*(260/396)=93*(260/396)No=105*(136/396)=116*(136/396)=93*(136/396)Now that we calculated the Expected Counts we need to find the Test Statistic.Test Stat = You will need to all 8 Count values but I am only showing you 3 because there isn't room to write out the entire equation.Question 13 of 201.0/ 1.0 PointsClick to see additional instructionsA local gym is looking in to purchasing more exercise equipment and runs a survey to find out the preference in exercise equipment amongst their members. They categorize the members based on how frequently they use the gym each month – the results are
below. Run an independence test at the 0.01 level of significance.Free WeightsWeightMachinesEnduranceMachinesAerobicsEquipment0-10 Uses1217251311-30 Uses20189931+ Uses2612119Enter the P-Value - round to 4 decimal places.0.0144Answer Key:0.0144Feedback:We are running a Chi-Square Test for Independence. Copy and Paste the table into Excel. You are given the Observed Counts in the table. Next you need to sum the rows and columns. Once you have those you need to calculate the Expected Counts. You need to find the probability of the row and then multiple it by the column total.Free WeightsWeight MachinesEndurance Machines0-10 Uses12172511-30 Uses2018931+ Uses261211Sum5847Free WeightsWeight MachinesEndurance Machines0-10 Uses=58*(67/181)=47*(67/181)=45*(67/181)11-30 Uses=58*(56/181)=47*(56/181)=45*(56/181)31+ Uses=58*(58/181)=47*(58/181)=45*(58/181)Now that we calculated the Expected Count we can use Excel to find the p-value. Use =CHISQ.TEST(highlight actual counts, highlight expected counts) = 0.0144Question 14 of 201.0/ 1.0 PointsA public opinion poll surveyed a simple random sample of 550 voters in Oregon. The respondents were asked which political party they identified with most and were categorized by residence. Results are shown below. Decide if voting preference is independent from location of residence. Let α=0.05.
RepublicanDemocratIndependentNW Oregon8510322SW Oregon456610Central Oregon46539Eastern Oregon673311Can it be concluded that voting preference is dependent on location of residence?