18 710711 Find the inverse of each one to one function Graph the function and

18 710711 find the inverse of each one to one

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18. 710711 Find the inverse of each one-to-one function. Graph the function and its inverse on one coordinate plane. 19. J = {(8, 2), (1, 1), (0, 0), ( 8, 2)} 20. K = {( 7, 1), (6, 2), (3, 1), (2, 5)} Page 36 of 47 Print | Beginning & Intermediate Algebra 1/31/2014 ...
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PRINTED BY: [email protected] Printing is for personal, private use only. No part of this book may be reproduced or transmitted without publisher's prior permission. Violators will be prosecuted. Find the inverse of each function. 21. f ( x ) = 4 x 5 22. f ( x ) = 8 3 x 23. f ( x ) = x 3 + 7 24. f ( x ) = 3 x 3 25. f open parenthesis x close parenthesis equals 4 over x 26. f open parenthesis x close parenthesis equals 3 over x 27. f open parenthesis x close parenthesis equals 4 over begin denominator x 5 end denominator 28. f open parenthesis x close parenthesis equals 2 over begin denominator 3 plus x end denominator For the given function f and its inverse, find f [ f 1 ( x )] . 29. f open parenthesis x close parenthesis equals begin numerator x 3 end numerator over 5 semicolon f to the 1 open parenthesis x close parenthesis equals 5 x plus 3 power 30. f open parenthesis x close parenthesis equals x over 2 plus 1 semicolon f to the 1 open parenthesis x close parenthesis power equals 2 x 2 Find the inverse of each function. Graph the function and its inverse on one coordinate plane. Graph the line y = x as a dashed line. 31. g ( x ) = 2 x + 5 32. f ( x ) = 3 x + 4 Page 37 of 47 Print | Beginning & Intermediate Algebra 1/31/2014 ...
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PRINTED BY: [email protected] Printing is for personal, private use only. No part of this book may be reproduced or transmitted without publisher's prior permission. Violators will be prosecuted. 33. h open parenthesis x close parenthesis equals 1 over 2 x 2 34. p open parenthesis x close parenthesis equals 2 over 3 x 4 35. r ( x ) = 3 x 1 36. k ( x ) = 3 2 x Page 38 of 47 Print | Beginning & Intermediate Algebra 1/31/2014 ...
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PRINTED BY: [email protected] Printing is for personal, private use only. No part of this book may be reproduced or transmitted without publisher's prior permission. Violators will be prosecuted. 711712 To Think About 37. Can you find an inverse function for the function f ( x ) = 2 x 2 + 3? Why or why not? 38. Can you find an inverse function for the function f ( x ) = | 3 x + 4| ? Why or why not? For every function f and its inverse, f 1 it is true that f [ f 1 ( x )] = x and f 1 [ f ( x )] = x . Show that this is true for each pair of inverse functions. 39. f open parenthesis x close parenthesis equals 2 x plus 3 over 2 to the comma power f to the 1 open parenthesis x close parenthesis power equals 1 over 2 x 3 over 4 40.
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