its node separation with the sine of the incident angle the distance separating

# Its node separation with the sine of the incident

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it’s node separation with the sine of the incident angle, the distance separating the two atoms, multiplied by 2. The slope of the sine is equal to the wavelength over 2 times the distance. 8.1 2 * d * sinθ = n * λ 8.2 m = λ / ( 2 * d ) Procedure The crystal is placed flat on the mount. The “atoms” are initially parallel to the incident microwave beam, at 180°. The crystal is then adjusted in increments of 2°, and the receiver is adjusted in increments of 4°. Rulers are used to mark off the Bragg planes and the normal to these, so that the crystal is properly aligned. This is repeated a multitude of times to record the three strongest peaks, out to n = 2. The Bragg planes experimented with in this procedure are shown below through d 1 and d 2 .
Physics 1600 with Richard Capobianco - Bragg Scattering 2 Data and Analysis Theoretical: d 1 = 4.00 cm d 2 = 5.2 cm λ = 2.85 cm Experimental: d 1 = 5.05 cm d 2 = 3.83 Percent error: 26.3% 26.3% For θ 1 = 5, 22, and 45, and θ 2 = 0, 22, and 32. For d 1 , the data shows multiple local maximum, of which there is only one global maximum. The value at which n = 1 for d, using equation 8.2, is 5.05 (where m is the slope of the graph of sinθ vs. n evaluated at each significant peak of the original θ vs. V graph). d = λ / ( 2 * m ) d = 0.0285 / ( 2 *0.2823 ) d = 5.05 cm The percent error between this value and the measured d 1 is 26.3%. | ( 4.0 - 5.05 ) / 4.0 | * 100 = 26.3% For d 2 , the data showed a weaker correlation, but by analyzing it through the same processes as d 1 , the theoretical distance d is found to be 3.83 cm for n = 1. The percent error

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• Fall '12
• BorisSinkovic
• Diffraction, Crystal, Crystallographic database, Bragg scattering

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