Term median 4 mode 4 q 3 p 75 i 75 12 17 100 75 q 3

This preview shows page 2 - 5 out of 8 pages.

term Median = 4 Mode = 4 Q 3 = P 75 : i = 75 . 12 ) 17 ( 100 75 = Q 3 is located at the 13 th term Q 3 = 4 P 11 : i = 87 . 1 ) 17 ( 100 11 = P 11 is located 2 nd term P 11 = 1 P 35 : i = 95 . 5 ) 17 ( 100 35 = P 35 is located 6 th term P 35 = 3 P 58 : i = 86 . 9 ) 17 ( 100 58 = P 58 is located 10 th term P 58 = 4 P 67 :i = 39 . 11 ) 17 ( 100 67 = P 67 is located 12 th term P 67 = 4 3.11 x x -µ (x-µ) 2 6 6-4.2857 = 1.7143 2.9388 2 2.2857 5.2244 4 0.2857 .0816 9 4.7143 22.2246 1 3.2857 10.7958 3 1.2857 1.6530 5 0.7143 .5102 Σ x = 30 Σ x-µ = 14.2857 Σ (x -µ) 2 = 43.4284 2857 . 4 7 30 = = Σ = N x μ a.) Range = 9 - 1 = 8 b.) M.A.D. = = = Σ 7 2857 . 14 N x μ 2.041 c.) σ 2 = 7 4284 . 43 ) ( 2 = Σ N x μ = 6.204 d.) σ = 204 . 6 ) ( 2 = Σ N x μ = 2.491 e.) 1, 2, 3, 4, 5, 6, 9 Q 1 = P 25 i = ) 7 ( 100 25 = 1.75 Q 1 is located at the 1 + 1 = 2 th term, Q 1 = 2 Q 3 = P 75 :i = ) 7 ( 100 75 = 5.25 Q 3 is located at the 5 + 1 = 6 th term, Q 3 = 6 IQR = Q 3 - Q 1 = 6 - 2 = 4
Image of page 2

Subscribe to view the full document.

Chapter 3: Descriptive Statistics 3 3.12 x x x 2 ) ( x x 4 0 0 3 1 1 0 4 16 5 1 1 2 2 4 9 5 25 4 0 0 5 1 1 Σ x = 32 x x Σ = 14 2 ) ( x x Σ = 48 8 32 = Σ = n x x = 4 a) Range = 9 - 0 = 9 b) M.A.D. = 8 14 = Σ n x x = 1.75 c) s 2 = 7 48 1 ) ( 2 = Σ n x x = 6.857 d) s = 857 . 6 1 ) ( 2 = Σ n x x = 2.619 e) Numbers in order: 0, 2, 3, 4, 4, 5, 5, 9 Q 1 =P 25 i = ) 8 ( 100 25 =2 Q 1 is located at the average of the 2 nd and 3 rd terms, Q 1 = (2 + 3)/2 = 2.5 th term Q 1 = 2.5 Q 3 = P 75 i = ) 8 ( 100 75 = 6 Q 3 is located at the average of the 6 th and 7 th terms Q 3 = (5 + 5)/2 = 5 IQR = Q 3 - Q 1 = 5 - 2.5 = 2.5 3.13 a.) x (x-µ) (x -µ) 2 12 12-21.167= -9.167 84.034 23 1.833 3.360 19 -2.167 4.696 26 4.833 23.358 24 2.833 8.026 23 1.833 3.360 Σ x = 127 Σ (x -µ) = -0.002 Σ (x -µ) 2 = 126.834 μ = 6 127 = Σ N x = 21.167 σ = 139 . 21 6 834 . 126 ) ( 2 = = Σ N x μ = 4.598 ORIGINAL FORMULA b.) x x 2 12 144 23 529 19 361 26 676 24 576 23 529 Σ x = 127 Σ x 2 = 2815 σ = 138 . 21 6 83 . 126 6 17 . 2688 2815 6 6 ) 127 ( 2815 ) ( 2 2 2 = = = = Σ Σ N N x x = 4.598 SHORT-CUT FORMULA The short-cut formula is faster.
Image of page 3
Chapter 3: Descriptive Statistics 4 3.14 s 2 = 433.9267 s = 20.8309 Σ x = 1387 Σ x 2 = 87,365 n = 25 x = 55.48 3.15 σ 2 = 58,631.359 σ = 242.139 Σ x = 6886 Σ x 2 = 3,901,664 n = 16 µ = 430.375 3.16 14, 15, 18, 19, 23, 24, 25, 27, 35, 37, 38, 39, 39, 40, 44, 46, 58, 59, 59, 70, 71, 73, 82, 84, 90 Q 1 = P 25 i = ) 25 ( 100 25 = 6.25 P 25 is located at the 6 + 1 = 7 th term Q 1 = 25 Q 3 = P 75 i = ) 25 ( 100 75 = 18.75 P 75 is located at the 18 + 1 = 19 th term Q 3 = 59 IQR = Q 3 - Q 1 = 59 - 25 = 34 3.17 a) 75 . 4 3 4 1 1 2 1 1 2 = = = b) 84 . 25 . 6 1 1 5 . 2 1 1 2 = = c) 609 . 56 . 2 1 1 6 . 1 1 1 2 = = d) 902 . 24 . 10 1 1 2 . 3 1 1 2 = = 3.18 Set 1: 5 . 65 4 262 1 = = Σ = N x μ 4 4 ) 262 ( 970 , 17 ) ( 2 2 2 1 = Σ Σ = N N x x σ = 14.2215 Set 2: 5 . 142 4 570 2 = = Σ = N x μ 4 4 ) 570 ( 070 , 82 ) ( 2 2 2 2 = Σ Σ = N N x x σ = 14.5344 CV 1 = ) 100 ( 5 . 65 2215 . 14 = 21.71% CV 2 = ) 100 ( 5 . 142 5344 . 14 = 10.20% 3.19 x x x 2 ) ( x x 7 1.833 3.361 5 3.833 14.694 10 1.167 1.361 12 3.167 10.028 9 0.167 0.028 8 0.833 0.694 14 5.167 26.694 3 5.833 34.028 11 2.167 4.694 13 4.167 17.361 8 0.833 0.694 6 2.833 8.028 106 32.000 121.665 12 106 = Σ = n x x = 8.833 a) MAD = 12 32 = Σ n x x = 2.667 b) s 2 = 11 665 . 121 1 ) ( 2 =
Image of page 4

Subscribe to view the full document.

Image of page 5

{[ snackBarMessage ]}

Get FREE access by uploading your study materials

Upload your study materials now and get free access to over 25 million documents.

Upload now for FREE access Or pay now for instant access
Christopher Reinemann
"Before using Course Hero my grade was at 78%. By the end of the semester my grade was at 90%. I could not have done it without all the class material I found."
— Christopher R., University of Rhode Island '15, Course Hero Intern

Ask a question for free

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern