106 6 5 100 5 16 5 2 s 4 4 16 1 5 90 106 1 5 1 5 s s

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106 6 ) 5 ( 100 ) 5 ( 16 ) 5 ( 2 = + + - = s 4 4 16 1 5 90 106 1 5 ) 1 ( ) 5 ( = = - - = - - s s The average rate of change is 4 ft/sec. s t s t s t t = - - ( ) ( ) , 1 1 1
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s t s t t t t ( ) ( ) - - = - + + - - 1 1 16 100 6 90 1 2 = - + - - 16 100 84 1 2 t t t ( 29 = - - + - 4 4 25 21 1 2 t t t ( 29 = - - + - 4 4 25 21 1 2 t t t = - - - - 4 4 21 1 1 ( )( ) t t t = - - 4 4 21 ( ) t
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c. Using the result found in part b, find the average rate of change of the height of the ball between 1 and 2 seconds. If t = 2, the average rate of change between 1 second and 2 seconds is: -4(4(2) - 21) = 52 ft/sec. Average Rate of Change between 1 second and t seconds is: -4(4t - 21)
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