7.2612Answer Key:7.2612Feedback:We are running a Chi-Square Test for Independence. Copy and Paste the table into Excel. You are given the Observed Counts in the table. Next you need to sum the rows and columns. Once you have those you need to calculate the Expected Counts. You need to find the probability of the row and then multiple it by the column total.AppliancesTVComputersCell PhonesBranch 156286324Branch 244225527Branch 353174933Branch 451316629Sum20498233113AppliancesTVComputersCell PhonesBranch 1=204*(171/648)=98*(171/648)=233*(171/648)=113*(171/648)Branch 2=204*(148/648)=98*(148/648)=233*(148/648)=113*(148/648)Branch 3=204*(152/648)=98*(152/648)=233*(152/648)=113*(152/648)Branch 4=204*(177/648)=98*(177/648)=233*(177/648)=113*(177/648)Now that we calculated the Expected Counts we need to find the Test Statistic.Test Stat = You will need to use all 16 Count values but I am only showing you the first and last value because there isn't room to write out the entire equation.Question 10 of 201.0/ 1.0 PointsA high school offers math placement exams for incoming freshmen to place students into the appropriate math class during their freshman year. Three different middle schools were sampled and the following pass/fail results were found. Run a test for independence at the 0.10 level of significance.

School ASchool BSchool CPass403350Fail594567Hypotheses: H0: Pass/fail rates are _____ school.H1: Pass/fail rates are _____school.Which of the following best fits the blank spaces above?A. independent of; independent onB. independent of, dependent onC. dependent of, dependent onD. dependent of, independent onAnswer Key:BQuestion 11 of 201.0/ 1.0 PointsAn electronics store has 4 branches in a large city. They are curious if sales in any particular department are different depending on location. They take a random sample of 4 purchases throughout the 4 branches – the results are recorded below. Run an independence test for the data below at the 0.05 level of significance.AppliancesTVComputersCell PhonesBranch 156286324Branch 244225527Branch 353174933Branch 451316629Can it be concluded that sales in the various departments are dependent on branch?

A. No, it cannot be concluded that sales in the various departments are dependent on branch because the p-value = 0.6099B. No, it cannot be concluded that sales in the various departments are dependent on branch because the p-value = 0.3901C. Yes, it can be concluded that sales in the various departments are dependent on branch because the p-value = 0.3901D. Yes, it can be concluded that sales in the various departments are dependent on branch because the p-value = 0.6099Answer Key:AFeedback:We are running a Chi-Square Test for Independence. Copy and Paste the table into Excel. You are given the Observed Counts in the table. Next you need to sum the rows and columns. Once you have those you need to calculate the Expected Counts. You need to find the probability of the row and then multiple it by the column total.