5) For a tdistribution with 16 degrees of freedom, find the area, or probability, in each region. (to 2 decimals)a.To the right of 2.120.025b.To the left of 1.337.9c.To the left of -1.746.05d.To the right of 2.583 e.Between -2.120 and 2.120 f. 6) The following sample data are from a normal population: 10, 8, 12, 16, 13, 11, 6, 4.a. What is the point estimate of the population mean? b. What is the point estimate of the population standard deviation (to 2 decimals)? (10-10)^2, (10-8)^2, (10-12)^2, (10-16)^2, (10-13)^2, (10-11)^2, (10-6)^2, (10-4)^2 c. With 95% confidence, what is the margin of error for the estimation of the population mean (to 1 decimal)? d. What is the 95% confidence interval for the population mean (to 1 decimal)?
7) Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of 55 weekly reports showed a sample mean of 17.5 customer contacts per week. The sample standard deviation was 5.6. Provide 90% and 95% confidence intervals for the population mean number of weekly customer contacts for the sales personnel. 8) The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maximum possible rating is 10. Suppose a simple random sample of 50 business travelers is selected and each traveler is asked to provide a rating for the Miami International Airport. The ratings obtained from the sample of 50 business travelers follow. 9) The average cost per night of a hotel room in New York City is $269 (SmartMoney, March 2009). Assume this estimate is based on a sample of 45 hotels and that the sample standard deviation is $65.a. With 95% confidence, what is the margin of error? Round your answer to the nearest dollar.
You've reached the end of your free preview.
Want to read all 10 pages?