Ligand addition d cpfemeco 2 pph 3 cpfeacylcopph 3

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ligand addition d) CpFe(Me)(CO) 2 + PPh 3 CpFe(acyl)(CO)(PPh 3 ) (acyl = C O CH 3 ) 1. Migratory insertion of CO and Me ligands to make acyl 2. PPh 3 ligand addition e) DELETED THE QUESTION WITHOUT RE-NUMBERING f) PtCl 2 (CH 2 CH 3 ) 2 (PMe 3 ) 2 PtCl 2 (PMe 3 ) 2 + CH 2 =CH 2 + CH 3 CH 3 1. Cl ligand dissociation (must make empty orbital for -hydride elimination, Cl is weakest binding ligand) 2. -hydride elimination to make Pt-H(ethylene) complex 3. CH 2 =CH 2 ligand dissociation 4. Reduction elimination of H and CH 2 CH 3 (steps 3 and 4 in either order) 5. Cl ligand addition g) [Cp 2 Mo(H)(CH 2 =CH 2 )] + + PPh 3 [Cp 2 Mo(CH 2 CH 3 )(PPh 3 )] + 1. Migratory insertion of H and ethylene ligand to make Mo-CH 2 CH 3 2. PPh 3 ligand addition h) [Cp 2 TiCH 3 ] + + CH 2 =CH 2 [Cp 2 Ti(CH 2 CH 2 CH 3 )] + 1. Ligand Addition of ethylene 2. 1,2-migratory insertion to give propyl ligand
7) Filling in the Reactivity Blanks Me 2 NCH 2 Ph reacts with PdCl 2 to give complex A . Complex A reacts with 3,3-dimethylcyclopropane and pyridine to give a mixture of complex C and D . Identify and draw complex A and explain the steps of the reactions. Why is it that Me 2 NPh does not give a product similar to complex A when treated with PdCl 2 ?

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