BUT PbI 2 s The process reaches equilibrium dissolving precipitating Chem 1036

But pbi 2 s the process reaches equilibrium

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BUT, PbI 2 ( s ) The process reaches equilibrium: dissolving precipitating
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Chem 1036 Chapter 19 45 of 50 Write the expression for the equilibrium constant: K sp = K sp : Consider: Ag 2 SO 4 ( s ) K sp = = 1.5x10 –5 CaF 2 ( s ) K sp = = 3.2x10 –11 Cu(OH) 2 (s) K sp = = 2.2x10 –20 The smaller the value of K sp : Chem 1036 Chapter 19 46 of 50 Compound K sp Compound K sp Al(OH) 3 3 x 10 –34 Fe(OH) 3 1.6 x 10 –39 BaCO 3 2.0 x 10 –9 PbCl 2 1.7 x 10 –5 BaF 2 1.5 x 10 –6 PbI 2 7.9 x 10 –9 Bi 2 S 3 1.0 x 10 –97 MgCO 3 3.5 x 10 –8 CaCO 3 3.3 x 10 –9 MgF 2 7.4 x 10 –9 CaF 2 3.2 x 10 –11 Ag 3 PO 4 2.6 x 10 –18 Ca(OH) 2 6.5 x 10 –6 AgCl 1.8 x 10 –10 CuCl 1.9 x 10 –7 AgI 8.3 x 10 –17 Cu 2 S 2.0 x 10 –47 Ag 2 S 8 x 10 –48 See Appendix C on page A-13 for additional K sp values Chem 1036 Chapter 19 47 of 50 Example Problem : The solubility of Pb(IO 3 ) 2 is 4.0 x 10 –5 mol/L at 25 o C. Calculate the value of K sp . Note: the solubility given is the amount of salt that has dissolved at equilibrium. Write the reaction and K sp expression: Chem 1036 Chapter 19 48 of 50 Example Problem: Calculate the solubility of Ag 3 PO 4 . ( K sp = 2.6 x 10 –18 ) Solubility: has much salt has dissolved at equilibrium? Write the reaction and K sp expression:
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Chem 1036 Chapter 19 49 of 50 Example Problem: Calculate the molar solubility of Ag 3 PO 4 in a 0.10 M AgNO 3 solution. Note: AgNO 3 is a soluble salt (complete reaction): AgNO 3 ( s ) o Ag + ( aq ) + NO 3 ( aq ) 0.10 M Write the reaction and K sp expression: There are two sources of the COMMON ION, Ag + : Chem 1036 Chapter 19 50 of 50 Common Ion Effect : We are not covering Section 19.4.
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