Red blue green yellow observed counts 7 18 9 11

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Red Blue Green Yellow Observed Counts 7 18 9 11 Expected Counts 11.2515.75 9 9 A. Yes, the p-value = 0.501025 B. No, the p-value = 0.501025 C. No, the p-value = 0.498975 D. Yes, the p-value = 0.498975 Answer Key: Feedback: Use Excel to find the p-value you have the Observed and Expected Counts you can use =CHISQ.TEST( Highlight Observed Counts, Highlight Expected Counts) = 0.498975 0.498975 > .05, Do Not Reject Ho. No, this is not significant. C
Question 7 of 20
An urban economist is curious if the distribution in where Oregon residents live is different today than it was in 1990. She observes that today there are approximately 3,109 thousand residents in NW Oregon, 902 thousand residents in SW Oregon, 244 thousand in Central Oregon, and 102 thousand in Eastern Oregon. She knows that in 1990 the breakdown was as follows: 72.7% NW Oregon, 20.7% SW Oregon, 4.8% Central Oregon, and 2.8% Eastern Oregon. Can she conclude that the distribution in residence is different today at a 0.05 level of significance? C
0.0/ 1.0 Points Question 8 of 20 A college prep school advertises that their students are more prepared to succeed in college than other schools. To verify this, they categorize GPA’s into 4 groups and look up the proportion of students at a state college in each category. They find that 7% have a 0-0.99, 21% have a 1-1.99, 37% have a 2-2.99, and 35% have a 3-4.00 in GPA. They then take a random sample of 200 of their graduates at the state college and find that 19 has a 0-0.99, 28 have a 1-1.99, 82 have a 2-2.99, and 71 have a 3-4.00. Can they conclude that the grades of their graduates are distributed differently than the general population at the school? Test at the 0.05 level of significance.
B
1.0/ 1.0 Points Question 9 of 20 A high school offers math placement exams for incoming freshmen to place students into the appropriate math class during their freshman year. Three different middle schools were sampled and the following pass/fail results were found. Run a test for independence at the 0.10 level of significance. School A School B School C Pass 40 33 50 Fail 59 45 67 Hypotheses: H 0 : Pass/fail rates are _____ school. H 1 : Pass/fail rates are _____school. Which of the following best fits the blank spaces above? Feedback: 0-0.99 1-1.99 2-2.99 3-4.00 Observed Counts 19 28 82 71 Expected Counts =200*0.07 =14 =200*.21= 42 =200*.37 = 74 =200*.35 = 70 You can use Excel to find the p-value =CHISQ.TEST(Highlight Observed, Highlight Expected) p-value = .0620 > .05, Do Not Reject Ho. No, this is not significant. Part 2 of 4 - Chi Square Test for Independence 4.0/ 6.0 Points
1.0/ 1.0 Points

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