Electrical equivalent of heat = 1.033 J/calPercent Difference = | 1.033 - 4.184| / (4.184) * 100% = 75%4.DISCUSSION2. Compare your result with the accepted value of J=4.184 joules/cal by calculating the percent difference between them. Is your result larger or smaller than the accepted value? Discuss the sources of errors.5.CONCLUSIONThis experiment was completed in order for our group to have a further understanding ofthe electrical equivalent of heat. The lab was able to depict the relationship between power,voltage, and the J value. The equations helped clarify the units of the joule value. Commonhuman error is prevalent in this situation due to not stopping the stopwatch at exactly twominutes each time. Also, measuring the voltage and amps could have been read inaccuratelyaccording to what was shown.