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X673 beats per minute s151 beats per minute use these

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x=67.3beats per minute,s=15.1beats per minuteUse these values to calculate the coefficient of variation for the male pulse rates. Round the result to onedecimal place.CV = sx•100= 15.167.3•100= 22.4%Now, find the coefficient of variation for the female pulse rates. While the mean and standard deviationcan be calculated using either the formulas or technology, for this problem, use technology. Find themean and standard deviation for the female pulse rates, rounding the results to one decimal place.x=78.1beats per minute,s=5.8beats per minuteUse these values to calculate the coefficient of variation for the female pulse rates. Round the result toone decimal place.
CV = sx•100= 5.878.1•100= 7.4%Therefore, the coefficient of variation for the male pulse rates is22.4%,and the coefficient for the female pulse rates is7.4%.Use these coefficients to determine whether the variation in the data sets is significantly different.
cm. Use this information to determine whether the adult male foot length of
22.5cm is significantly low or significantly high.To use the givenformula, first find the midpoint of each class.Interval40-4950-5960-6970-7980-8990-99100-109x=classmidpoint44.554.564.574.584.594.5104.5Now find n.n=97The values of f and x are given in the table below.Interval40-4950-5960-6970-7980-8990-99100-109Frequency1131163738x=classmidpoint44.554.564.574.584.594.5104.5It will be helpful to solve this in parts.First, findf•x2.f•x2=f1•x12+f2•x22+f3•x32+•••+f7•x72=1•44.52+1•54.52+3•64.52+•••+38•104.52= 882,614.25Next, find(f•x)2.(f•x)2=f1•x1+f2•x2+f3•x3+•••+f7•x72=[(1•44.5)+(1•54.5)+(3•64.5)+•••+(38•104.5)]2=84,391,782Now solve for the standarddeviation, rounding to one decimal place.s=nf•x2(f•x)2n(n−1)=97•[882,614.25]−84,391,78297(97−1)=11.5Consider a difference of20% between two values of a standard deviation to be significant.The ratio of the computed value to the given value is1.036:1.This corresponds to a3.6%difference.Thus, the computed value is not significantly different from the given value.a.The empirical rule states that for data sets having a distribution that is approximatelybell-shaped, thefollowing properties apply.About68% of all values fall within 1 standard deviation of the mean.

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Term
Fall
Professor
mr.darmo

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