0 10 Points Free Weights Weight Machines Endurance Machines Aerobics Equipment

# 0 10 points free weights weight machines endurance

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0.0/ 1.0 Points Free Weights Weight Machines Endurance Machines Aerobics Equipment Sum 0-10 Uses 12 17 25 13 67 11-30 Uses 20 18 9 9 56 31+ Uses 26 12 11 9 58 Sum 58 47 45 31 181 Free Weights Weight Machines Endurance Machines Aerobics Equipment 0-10 Uses =58*(67/181) =47*(67/181) =45*(67/181) =31*(67/181) 11-30 Uses =58*(56/181) =47*(56/181) =45*(56/181) =31*(56/181) 31+ Uses =58*(58/181) =47*(58/181) =45*(58/181) =31*(58/181) Now that we calculated the Expected Count we can use Excel to find the p-value. Use =CHISQ.TEST(highlight actual counts, highlight expected counts) = 0.0144 Question 12 of 20 Click to see additional instructions The following sample was collected during registration at a large middle school. At the 0.05 level of significance, can it be concluded that level of math is dependent on grade level? Honors Math Regular Math General Math 6 th Grade 35 47 14 7 th Grade 37 49 12 8 th Grade 33 48 19 Enter the missing values in the expected matrix - round to 4 decimal places. Honors Math Regular Math General Math 6 th Grade 7 th Grade 35 48 15 8 th Grade Answer Key: 34.2857, 47.0204, 14.6939, 35.7143, 48.9796, 15.3061 0.0/ 1.0 Points Feedback: We are running a Chi-Square Test for Independence. Copy and Paste the table into Excel. You are given the Observed Counts in the table. We need to calculate the Expected Counts. Then sum up the rows and column. You need to find the probability of the row and then multiple it by the column total. Honors Math Regular Math General Math Sum 6th Grade 35 47 14 96 7th Grade 37 49 12 98 8th Grade 33 48 19 100 Sum 105 144 45 294 Honors Math Regular Math General Math 6th Grade =105* (96/294) =144*(96/294) =45*(96/294) 7th Grade =105* (98/294) =144*(98/294) =45*(98/294) 8th Grade =105* (100/294) =144*(100/294) =45* (100/294) Question 13 of 20 Click to see additional instructions An electronics store has 4 branches in a large city. They are curious if sales in any particular department are different depending on location. They take a random sample of 4 purchases throughout the 4 branches – the results are recorded below. Run an independence test for the data below at the 0.05 level of significance. Appliances TV Computers Cell Phones Branch 1 56 28 63 24 Branch 2 44 22 55 27 Branch 3 53 17 49 33 Branch 4 51 31 66 29 Enter the test statistic - round to 4 decimal places. Answer Key: 7.2612 Feedback: 0.0/ 1.0 Points We are running a Chi-Square Test for Independence. Copy and Paste the table into Excel. You are given the Observed Counts in the table. Next you need to sum the rows and columns. Once you have those you need to calculate the Expected Counts. You need to find the probability of the row and then multiple it by the column total. Appliances TV Computers Cell Phones Sum Branch 1 56 28 63 24 171 Branch 2 44 22 55 27 148 Branch 3 53 17 49 33 152 Branch 4 51 31 66 29 177 Sum 204 98 233 113 648 Appliances TV Computers Cell Phones Branch 1 =204*(171/648) =98*(171/648) =233*(171/648) =113*(171/648) Branch 2 =204*(148/648) =98*(148/648) =233*(148/648) =113*(148/648) Branch 3 =204*(152/648) =98*(152/648) =233*(152/648) =113*(152/648) Branch 4 =204*(177/648) =98*(177/648) =233*(177/648) =113*(177/648) Now that we calculated the Expected Counts we need to find the Test Statistic.  • • • 