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The file opened successfully George,Darby 166.2 Dee,Helen 143.5 Lupa,Giovanni 192.4 Donovan,Cat 215.1 The average weight is 179.300000 File close successful
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Name: Grant Jensen AERE 161, Spring 2018 HW #6 Due date: 03/07/2018 Problem 12.10 clear, clc %Grant Jensen, AER E 161, Homework #6, Problem 12.10 %Loads the file windturbinedata.dat load windturbinedata.dat %Then it creates vectors for blade diameter, wind velocity, and electricity %generated d = windturbinedata(:,1); v = windturbinedata(:,2); E = windturbinedata(:,3); %Then it creates a 3-D plot of the relationship between the 3 stem3(d,v,E); xlabel( 'Blade Diameter (ft)' ) ylabel( 'Wind Velocity (mph)' ) zlabel( 'Electricity Generated (kW-hr/year)' ) title( 'Wind Turbine Data' ) Output:
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Name: Grant Jensen AERE 161, Spring 2018 HW #6 Due date: 03/07/2018 Problem 14.1 clear, clc %Grant Jensen, AER E 161, Homework #6, Problem 14.1 prod_line_A = [15.94, 15.98, 15.94, 16.16, 15.86, 15.86, 15.90, 15.88] prod_line_B = [15.96, 15.94, 16.02, 16.10, 15.92, 16.00, 15.96, 16.02] %Determines mean, median, mode, and the standard deviation for A mean_prod_line_A = mean(prod_line_A); median_prod_line_A = median(prod_line_A); mode_prod_line_A = mode(prod_line_A); std_prod_line_A = std(prod_line_A); %Determines mean, median, mode, and the standard deviation for B mean_prod_line_B = mean(prod_line_B); median_prod_line_B = median(prod_line_B); mode_prod_line_B = mode(prod_line_B); std_prod_line_B = std(prod_line_B); %Creates a table of the values we just calculated data_A_and_B = table({ 'Production Line A' ; 'Production Line B' },[mean_prod_line_A ; mean_prod_line_B],[median_prod_line_A ; median_prod_line_B],[mode_prod_line_A ; mode_prod_line_B],[std_prod_line_A ; std_prod_line_B]); data_A_and_B.Properties.VariableNames = { 'Production_Line' 'Mean' 'Median' 'Mode' 'Standard_Deviation' }; disp(data_A_and_B) Output: prod_line_A = 15.9400 15.9800 15.9400 16.1600 15.8600 15.8600 15.9000 15.8800 prod_line_B = 15.9600 15.9400 16.0200 16.1000 15.9200 16.0000 15.9600 16.0200 Production_Line Mean Median Mode Standard_Deviation ___________________ ______ ________ ______ _______________________ 'Production Line A' 15.94 15.92 15.86 0.098561 'Production Line B' 15.99 15.98 15.96 0.05757 All values are in millimeters (mm) Based on this data, production line B is better at producing marbles of the desired diameter of 16 mm. Not only is the standard deviation smaller than that of
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