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Round your answer to two decimal places.Enter a minus sign if your answer is negative.)(Round your answer to two decimal places.)
Question 38)Suppose that a researcher, using data on class size (CS) and average test scores from 106 third-gradeclasses, estimates the OLS regressionTestScore=483.972+(5.4126)×CS,R2=0.11,SER=10.7.A classroom has 25 students. The regression's prediction for that classroom's average test score is348.66.483.972 + (-5.4126) * 25 = 348.66Last year a classroom had 22 students, and this year it has 26 students. The regression's prediction forthe change in the classroom average test score is- 21.65((-5.4126) * 26)((5.4126) * 22) = -21.65(Round your response to two decimal places.)The sample average class size across the 106 classrooms is 19.90. The sample average of the testscores across the 106 classrooms is376.26483.972 + ( - 5.4126) * 19.90= 376.26(Hint:Review the formulas for the OLS estimators.)(Round your response to two decimal places.)The sample standard deviation of test scores across the 106 classrooms isTOO LONG, WASTE OF TIME(Hint:Review the formulas for theR2andSER(Round your response to one decimal place.).)
Question 39)Suppose that a random sample of 200 twenty-year-old men is selected from a population and that thesemen's height and weight are recorded. A regression of weight on height yieldsWeight=(−100.4041)+3.9794×Height,R2=0.82,SER=10.3,whereWeightis measured in pounds andHeightis measured in inches. What is the regression's weightprediction for someone who is 72 inches tall? The regression's weight prediction for someone who is72 inches tall is186.1127(- 100.4041) + 3.9794 * 72 = 186.1127pounds.(Round your response to two decimal places.)man has a late growth spurt and grows 1.5 inches over the course of a year. What is the regression'sprediction for the increase in this man's weight?The regression's prediction for the increase in this man's weight is5.973.9794 * 1.5 = 5.97pounds.(Round your response to two decimal places.)Suppose that instead of measuring weight and height in pounds and inches these variables are measuredin centimeters and kilograms (1in= 2.54cmand 1lb= 0.4536kgSuppose the regression equation in centimeter-kilogram units is:Weight=γ0+γ1Height.The regression estimates from this new centimeter-kilogram regression are:γ0=nothing kg.( - 100.4041) * 0.4536 = - 45.5433(Round your response to four decimal places.)γ1=nothing kg per cm.3.9794 * ( 0.4536 / 2.54) = 0.7107(Round your response to four decimal places.)R2=nothing .0.82 (remains as is)(Round your response to two decimal places.)).

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