IE5541-HW6

# 9 f 1 7 13 7 4 g 4 10 28 12 16 h 2 5 14 6 4 i 5 8 17

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9 F 1 7 13 7 4 G 4 10 28 12 16 H 2 5 14 6 4 I 5 8 17 9 4 J 2 5 8 5 1 K 17 29 45 30 22 Actual time t e for A: (a+4m+b)/6 = (4+4*7+10)/6 = 42/6 = 7 Actual time t e for B: (a+4m+b)/6 = (2+4*4+8)/6 = 26/6 = 4.33= 4 Actual time t e for C: (a+4m+b)/6 = (2+5*4+8)/6 = 30/6 = 5 Actual time t e for D: (a+4m+b)/6 = (16+19*4+28)/6 = 20 Actual time t e for E: (a+4m+b)/6 = (6+9*4+24)/6 = 11 Actual time t e for F: (a+4m+b)/6 = (1+4*7+13)/6 = 7 Actual time t e for G: (a+4m+b)/6 = (4+4*10+28)/6 = 12 Actual time t e for H: (a+4m+b)/6 = (2+4*5+14)/6 = 6 Actual time t e for I: (a+4m+b)/6 = (5+4*8+17)/6 = 9 Actual time t e for J: (a+4m+b)/6 = (2+4*5+8)/6 = 5 Actual time t e for K: (a+4m+b)/6 = (17+29*4+45)/6 = 29.67 = 30. Variance for A: [(b-a)/6] 2 = [(10-4)/6] 2 = 1 Variance for B: [(b-a)/6] 2 = [(8-2)/6] 2 = 1 Variance for C: [(b-a)/6] 2 = [(8-2)/6] 2 = 1 Variance for D: [(b-a)/6] 2 = [(28-16)/6] 2 = 4 Variance for E: [(b-a)/6] 2 = [(24-6)/6] 2 = 9 Variance for F: [(b-a)/6] 2 = [(13-1)/6] 2 =4 Variance for G: [(b-a)/6] 2 = [(28-4)/6] 2 =16 Variance for H: [(b-a)/6] 2 = [(14-2)/6] 2 =4 Variance for I: [(b-a)/6] 2 = [(17-5)/6] 2 =4 Variance for J: [(b-a)/6] 2 = [(8-2)/6] 2 =1 Variance for K: [(b-a)/6] 2 = [(45-17)/6] 2 =21.78 = 22

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The AON network diagram for the project looks as follows. 0 B 4 4 A-C-D-H-J-K = 7+5+20+6+5+30 = 73 A-C-E-F-H-J-K = 7+5+11+7+6+5+30 = 71 A-C-G-H-J-K = 7+5+12+6+5+30 = 65 A-C-G-I-K = 7+5+12+9+30 = 63 B-C-D-H-J-K = 4+5+20+6+5+30 = 70 B-C-E-F-H-J-K = 4+5+11+7+6+5+30 = 68 B-C-G-H-J-K = 4+5+12+6+5+30 = 62 B-C-G-I-K = 4+5+12+9+30 = 60 Therefore critical path is A-C-D-F-J-K which is 73 days. The project completion time T E is 73 days.
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