HW6_Solutions

# 1 000204 g 2 219 g 3 0466 g 4 0000178 g 5 136 g 6

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1. 0.00204 g 2. 2.19 g 3. 0.466 g 4. 0.000178 g 5. 1.36 g 6. 0.129 g correct 7. 0.0112 g 8. 0.0000324 g 9. 5.49 g Explanation: pH = 3 . 75 V = 11 . 5 L MM = 63 . 1 g/mol [H + ] = 10 pH = 10 3 . 75 = 0 . 000177828 Since HNO 3 is a strong acid, HNO 3 (aq) H + (aq) + NO 3 (aq) . One HNO 3 one H + , so [H + ] = [HNO 3 ] = 0 . 000177828 M and (11 . 5 L) × 0 . 000177828 mol HNO 3 1 L = 0 . 00204502 mol HNO 3 . Thus (0 . 00204502 mol HNO 3 ) × 63 . 1 g HNO 3 1 mol HNO 3 = 0 . 129041 g HNO 3
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• Fall '07
• Holcombe
• pH, Acids, Hydronium, ESTRADA

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