Let the location of the image be denoted as q q p h h

Let the location of the image be denoted as
q .
or
R =
2 p q
p + q
=
2 (41 . 3 cm) (289 . 1 cm)
41 . 3 cm + 289 . 1 cm
= 72 . 275 cm .
012 10.0points
A spherical Christmas tree ornament is
3 . 76 cm in diameter.
What is the magnification of the image of
an object placed 13 . 3 cm away from the orna-
ment?
Correct answer: 0 . 0660112.
Explanation:
Let : p = 13 . 3 cm and
R =
- 3 . 76 cm
2
= - 1 . 88 cm .
q
p
h
h'
f
R
Since the image is 7 times larger than the
object, and is a real image, as stated in the
problem ( p > 0 and q > 0), the magnification
must be negative; i.e. , M = - 7.
M =
h
′
h
= -
q
p
= - 7 ,
so
q = - M p = - ( - 7) (41 . 3 cm) = 289 . 1 cm .
011(part2of2)10.0points
What is the radius of curvature of the mirror?
R
or
R =
2 p q
p + q
=
2 (41 . 3 cm) (289 . 1 cm)
41 . 3 cm + 289 . 1 cm
= 72 . 275 cm .
012 10.0points
A spherical Christmas tree ornament is
3 . 76 cm in diameter.
What is the magnification of the image of
an object placed 13 . 3 cm away from the orna-
ment?
Correct answer: 0 . 0660112.
Explanation:
Let : p = 13 . 3 cm and
R =
- 3 . 76 cm
2
= - 1 . 88 cm .

segovia (cs39966) – Homework 8 – Spurlock – (14441) 5
Using the mirror equation,
1
f
=
2
R
=
1
p
+
1
10.0points
The magnification produced by a converging
lens is found to be 2 . 7 for an object placed
21 cm from the lens.
What is the focal length of the lens?
013 10.0points
A convex mirror has a focal length of - 24 cm.
What is the object distance if the image
distance is - 17 . 1 cm?
> p > f f < q < ∞ 0 > m > -∞
f > p > 0 -∞ < q < 0 ∞ > m > 1
014 10.0points
The magnification produced by a converging
lens is found to be 2 . 7 for an object placed
21 cm from the lens.
What is the focal length of the lens?
∞ > p > f f < q < ∞ 0 > m > -∞
f > p > 0 -∞ < q < 0 ∞ > m > 1
What is the distance between the object
and the lens?

segovia (cs39966) – Homework 8 – Spurlock – (14441) 6
1
p
+
1
q
=
1
f
M =
h
′
h
= -
q
p
Determine the magnification of the image.
016(part1of2)10.0points
017(part2of2)10.0points
Determine the magnification of the image.
An object is located 28 cm from a diverging
lens with a focal length of 36 cm.
Determine the image distance.