fall17mth143.practice2.8-Parametric.pdf

# Y solution solution we eliminate the parameter since

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y = Solution: Solution: We eliminate the parameter. Since x = ln ( 8 t ) , we have t = e x 8 . Substituting into y = 1 - t we obtain y = 1 - e x 8 Answer(s) submitted: (incorrect) Correct Answers: 1-eˆx/8 7. (1 point) Write the parametric equations x = 3sin 2 θ , y = 4cos 2 θ in the given Cartesian form. y = with 0 x 3. Answer(s) submitted: (incorrect) Correct Answers: 4*(1-x/3) 8. (1 point) Write the parametric equations x = 3sin θ , y = 8cos θ , 0 θ π in the given Cartesian form. y 2 64 = with x 0. Answer(s) submitted: (incorrect) Correct Answers: 1-xˆ2/3ˆ2 9. (1 point) Write the parametric equations x = 2 t - 1 , y = 2 - 3 t as a function of x in Cartesian form. y = Answer(s) submitted: (incorrect) Correct Answers: 2-3*(x+1)/2 Generated by c WeBWorK, , Mathematical Association of America 2
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• Fall '14
• Calculus, Parametric equation, Conic section

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